[shell] Unix ls command: show full path when using options

I often use this list command in Unix (AIX / KSH):

ls -Artl

It displays the files as this:

-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test1.txt
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test2.txt

I would like to modify the command such a way that the full path of the file is displayed. For example:

-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test1.txt
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test2.txt

Any ideas?

I found several resolution methods using pwd or find but - as far as I see - this does not work work if I want to keep the ls options.

You can combine the find command and the ls command. Use the path (.) and selector (*) to narrow down the files you're after. Surround the find command in back quotes. The argument to -name is doublequote star doublequote in case you can't read it.

ls -lart `find . -type f -name "*" `

I use this command:

ls -1 | xargs readlink -f

Use this command:

ls -ltr /mig/mthome/09/log/*

instead of:

ls -ltr /mig/mthome/09/log

to get the full path in the listing.

I wrote a shell script called fullpath that contains this code, use it everyday:

    #!/bin/sh
    for i in $* ; do
        echo $(pwd)/$i
    done

Put it somewhere in your PATH, and make it executable(chmod 755 fullpath) then just use
fullpath file_or_directory

simply use find tool.

find absolute_path

displays full paths on my Linux machine, while

find relative_path

will not.

Try this, works for me: ls -d /a/b/c/*

optimized from spacedrop answer ...

ls $(pwd)/*

and you can use ls options

ls -alrt $(pwd)/*