How to use mod operator in bash

Question

I m trying a line like this   for i in  1  600   do wget http   example com search link  i   5  done    What I m trying to get as output is   wget http   example com search link0 wget http   example com search link1 wget http   example com search link2 wget http   example com search link3 wget http   example com search link4 wget http   example com search link0   But what I m actually getting is just       wget http   example com search link

User · Answer

You must put your mathematical expressions inside $(( )).

One-liner:

for i in {1..600}; do wget http://example.com/search/link$(($i % 5)); done;

Multiple lines:

for i in {1..600}; do
    wget http://example.com/search/link$(($i % 5))
done

User · Answer

for i in  1  600  do     n     i 5       wget http   example com search link n done

User · Answer

This might be off-topic  But for the wget in for loop  you can certainly do   curl -O http   example com search link 1-600

User · Answer

Try the following    for i in  1  600   do echo wget http   example com search link    i   5    done   The           syntax does an arithmetic evaluation of the contents

[bash] How to use mod operator in bash?

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