django MultiValueDictKeyError error how do I deal with it

Question

I m trying to save a object to my database  but it s throwing a MultiValueDictKeyError error   The problems lies within the form  the is private is represented by a checkbox  If the check box is NOT selected  obviously nothing is passed  This is where the error gets chucked   How do I properly deal with this exception  and catch it    The line is  is private   request POST  is private

User · Accepted Answer

Use the MultiValueDict s get method  This is also present on standard dicts and is a way to fetch a value while providing a default if it does not exist   is private   request POST get  is private   False    Generally   my var   dict get  lt key gt    lt default gt

User · Answer

Another thing to remember is that request POST  keyword   refers to the element identified by the specified html name attribute keyword   So  if your form is    lt form action   login   method  POST  gt     lt input type  text  name  keyword  placeholder  Search query  gt     lt input type  number  name  results  placeholder  Number of results  gt   lt  form gt    then  request POST  keyword   and request POST  results   will contain the value of the input elements keyword and results  respectively

User · Answer

Choose what is best for you   1  is private   request POST get  is private   False     If is private key is present in request POST the is private variable will be equal to it  if not  then it will be equal to False   2  if  is private  in request POST      is private   request POST  is private   else      is private   False   3  from django utils datastructures import MultiValueDictKeyError try      is private   request POST  is private   except MultiValueDictKeyError      is private   False

User · Answer

You get that because you re trying to get a key from a dictionary when it s not there  You need to test if it is in there first   try   is private    is private  in request POST   or   is private    is private  in request POST and request POST  is private     depending on the values you re using

User · Answer

First check if the request object have the  is private  key parameter  Most of the case s this MultiValueDictKeyError occurred for missing key in the dictionary-like request object  Because dictionary is an unordered key  value pair    associative memories    or    associative arrays    In another word  request GET or request POST is a dictionary-like object containing all  request parameters  This is specific to Django  The method get   returns a value for the given key if key is in the dictionary  If key is not available then returns default value None   You can handle this error by putting   is private   request POST get  is private   False

User · Answer

For me  this error occurred in my django project because of the following   I inserted a new hyperlink in my home html present in templates folder of my project as below   x000D   x000D   lt input type  button  value  About  onclick  location href     url  about       gt  x000D   x000D   x000D    In views py  I had the following definitions of count and about       def count request              fulltext   request GET  fulltext              wordlist   fulltext split              worddict                 for word in wordlist                 if word in worddict                     worddict word     1                else                     worddict word    1                    worddict   sorted worddict items    key   operator itemgetter 1  reverse True             return render request  count html    fulltext  fulltext  count  len wordlist   worddict   worddict       def about request           return render request  quot about html quot     In urls py  I had the following url patterns       urlpatterns             path  admin    admin site urls           path    views homepage name  quot home quot            path  eggs  views eggs           path  count   views count name  quot count quot            path  about   views count name  quot about quot           As can be seen in no  3 above in the last url pattern  I was incorrectly calling views count whereas I needed to call views about  This line fulltext   request GET  fulltext   in count function  which was mistakenly called because of wrong entry in urlpatterns  of views py threw the multivaluedictkeyerror exception  Then I changed the last url pattern in urls py  to the correct one i e  path  about   views about name  quot about quot    and everything worked fine  Apparently  in general a newbie programmer in django can make the mistake I made of wrongly calling another view function for a url  which might be expecting different set of parameters or passing different set of objects in its render call  rather than the intended behavior  Hope this helps some newbie programmer to django

User · Answer

Why didn t you try to define is private in your models as default False   class Foo models Models       is private   models BooleanField default False

[python] django MultiValueDictKeyError error, how do I deal with it

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