[python] django MultiValueDictKeyError error, how do I deal with it

I'm trying to save a object to my database, but it's throwing a MultiValueDictKeyError error.

The problems lies within the form, the is_private is represented by a checkbox. If the check box is NOT selected, obviously nothing is passed. This is where the error gets chucked.

How do I properly deal with this exception, and catch it?

The line is

is_private = request.POST['is_private']

This question is related to python django exception

The answer is


For me, this error occurred in my django project because of the following:

  1. I inserted a new hyperlink in my home.html present in templates folder of my project as below:

    _x000D_
    _x000D_
    <input type="button" value="About" onclick="location.href='{% url 'about' %}'">
    _x000D_
    _x000D_
    _x000D_

  2. In views.py, I had the following definitions of count and about:

   def count(request):
           fulltext = request.GET['fulltext']
           wordlist = fulltext.split()
           worddict = {}
           for word in wordlist:
               if word in worddict:
                   worddict[word] += 1
               else:
                   worddict[word] = 1
                   worddict = sorted(worddict.items(), key = operator.itemgetter(1),reverse=True)
           return render(request,'count.html', 'fulltext':fulltext,'count':len(wordlist),'worddict'::worddict})

   def about(request): 
       return render(request,"about.html")
  1. In urls.py, I had the following url patterns:
    urlpatterns = [
        path('admin/', admin.site.urls),
        path('',views.homepage,name="home"),
        path('eggs',views.eggs),
        path('count/',views.count,name="count"),
        path('about/',views.count,name="about"),
    ]

As can be seen in no. 3 above,in the last url pattern, I was incorrectly calling views.count whereas I needed to call views.about. This line fulltext = request.GET['fulltext'] in count function (which was mistakenly called because of wrong entry in urlpatterns) of views.py threw the multivaluedictkeyerror exception.

Then I changed the last url pattern in urls.py to the correct one i.e. path('about/',views.about,name="about"), and everything worked fine.

Apparently, in general a newbie programmer in django can make the mistake I made of wrongly calling another view function for a url, which might be expecting different set of parameters or passing different set of objects in its render call, rather than the intended behavior.

Hope this helps some newbie programmer to django.


Choose what is best for you:

1

is_private = request.POST.get('is_private', False);

If is_private key is present in request.POST the is_private variable will be equal to it, if not, then it will be equal to False.

2

if 'is_private' in request.POST:
    is_private = request.POST['is_private']
else:
    is_private = False

3

from django.utils.datastructures import MultiValueDictKeyError
try:
    is_private = request.POST['is_private']
except MultiValueDictKeyError:
    is_private = False

First check if the request object have the 'is_private' key parameter. Most of the case's this MultiValueDictKeyError occurred for missing key in the dictionary-like request object. Because dictionary is an unordered key, value pair “associative memories” or “associative arrays”

In another word. request.GET or request.POST is a dictionary-like object containing all request parameters. This is specific to Django.

The method get() returns a value for the given key if key is in the dictionary. If key is not available then returns default value None.

You can handle this error by putting :

is_private = request.POST.get('is_private', False);

Another thing to remember is that request.POST['keyword'] refers to the element identified by the specified html name attribute keyword.

So, if your form is:

<form action="/login/" method="POST">
  <input type="text" name="keyword" placeholder="Search query">
  <input type="number" name="results" placeholder="Number of results">
</form>

then, request.POST['keyword'] and request.POST['results'] will contain the value of the input elements keyword and results, respectively.


You get that because you're trying to get a key from a dictionary when it's not there. You need to test if it is in there first.

try:

is_private = 'is_private' in request.POST

or

is_private = 'is_private' in request.POST and request.POST['is_private']

depending on the values you're using.


Why didn't you try to define is_private in your models as default=False?

class Foo(models.Models):
    is_private = models.BooleanField(default=False)

Examples related to python

programming a servo thru a barometer Is there a way to view two blocks of code from the same file simultaneously in Sublime Text? python variable NameError Why my regexp for hyphenated words doesn't work? Comparing a variable with a string python not working when redirecting from bash script is it possible to add colors to python output? Get Public URL for File - Google Cloud Storage - App Engine (Python) Real time face detection OpenCV, Python xlrd.biffh.XLRDError: Excel xlsx file; not supported Could not load dynamic library 'cudart64_101.dll' on tensorflow CPU-only installation

Examples related to django

How to fix error "ERROR: Command errored out with exit status 1: python." when trying to install django-heroku using pip Pylint "unresolved import" error in Visual Studio Code Is it better to use path() or url() in urls.py for django 2.0? Unable to import path from django.urls Error loading MySQLdb Module 'Did you install mysqlclient or MySQL-python?' ImportError: Couldn't import Django Django - Reverse for '' not found. '' is not a valid view function or pattern name Class has no objects member Getting TypeError: __init__() missing 1 required positional argument: 'on_delete' when trying to add parent table after child table with entries How to switch Python versions in Terminal?

Examples related to exception

Connection Java-MySql : Public Key Retrieval is not allowed How to print an exception in Python 3? ASP.NET Core Web API exception handling Catching FULL exception message How to get exception message in Python properly What does "Fatal error: Unexpectedly found nil while unwrapping an Optional value" mean? what does Error "Thread 1:EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0)" mean? Argument Exception "Item with Same Key has already been added" The given key was not present in the dictionary. Which key? sql try/catch rollback/commit - preventing erroneous commit after rollback