[linux] Automatically capture output of last command into a variable using Bash?

It can be done using the magic of file descriptors and the lastpipe shell option.

It has to be done with a script - the "lastpipe" option will not work in interactive mode.

Here's the script I've tested with:

$ cat shorttest.sh 
#!/bin/bash
shopt -s lastpipe

exit_tests() {
    EXITMSG="$(cat /proc/self/fd/0)"
}

ls /bloop 2>&1 | exit_tests

echo "My output is \"$EXITMSG\""


$ bash shorttest.sh 
My output is "ls: cannot access '/bloop': No such file or directory"

What I'm doing here is:

  1. setting the shell option shopt -s lastpipe. It will not work without this as you will lose the file descriptor.

  2. making sure my stderr also gets captured with 2>&1

  3. piping the output into a function so that the stdin file descriptor can be referenced.

  4. setting the variable by getting the contents of the /proc/self/fd/0 file descriptor, which is stdin.

I'm using this for capturing errors in a script so if there is a problem with a command I can stop processing the script and exit right away.

shopt -s lastpipe

exit_tests() {
    MYSTUFF="$(cat /proc/self/fd/0)"
    BADLINE=$BASH_LINENO
}

error_msg () {
    echo -e "$0: line $BADLINE\n\t $MYSTUFF"
    exit 1
}

ls /bloop 2>&1 | exit_tests ; [[ "${PIPESTATUS[0]}" == "0" ]] || error_msg

In this way I can add 2>&1 | exit_tests ; [[ "${PIPESTATUS[0]}" == "0" ]] || error_msg behind every command I care to check on.

Now you can enjoy your output!

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