find . -type f -name '*php' -o -name '*js' -o -name '*html' |\
xargs grep -liE 'document\.cookie|setcookie'
Sounds like a perfect job for grep or perhaps ack
Or this wonderful construction:
find . -type f \( -name *.php -o -name *.html -o -name *.js \) -exec grep "document.cookie\|setcookie" /dev/null {} \;
find them and grep for the string:
This will find all files of your 3 types in /starting/path and grep for the regular expression '(document\.cookie|setcookie)'. Split over 2 lines with the backslash just for readability...
find /starting/path -type f -name "*.php" -o -name "*.html" -o -name "*.js" | \
xargs egrep -i '(document\.cookie|setcookie)'
Just to include one more alternative, you could also use this:
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \;
Where:
-regextype posix-extended tells find what kind of regex to expect-regex "^.*\.(php|html|js)$" tells find the regex itself filenames must match-exec grep -EH '(document\.cookie|setcookie)' {} \; tells find to run the command (with its options and arguments) specified between the -exec option and the \; for each file it finds, where {} represents where the file path goes in this command.
while
E option tells grep to use extended regex (to support the parentheses) and...H option tells grep to print file paths before the matches.And, given this, if you only want file paths, you may use:
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \; | sed -r 's/(^.*):.*$/\1/' | sort -u
Where
| [pipe] send the output of find to the next command after this (which is sed, then sort) r option tells sed to use extended regex.s/HI/BYE/ tells sed to replace every First occurrence (per line) of "HI" with "BYE" and...s/(^.*):.*$/\1/ tells it to replace the regex (^.*):.*$ (meaning a group [stuff enclosed by ()] including everything [.* = one or more of any-character] from the beginning of the line [^] till' the first ':' followed by anything till' the end of line [$]) by the first group [\1] of the replaced regex.u tells sort to remove duplicate entries (take sort -u as optional)....FAR from being the most elegant way. As I said, my intention is to increase the range of possibilities (and also to give more complete explanations on some tools you could use).
Try something like grep -r -n -i --include="*.html *.php *.js" searchstrinhere .
the -i makes it case insensitlve
the . at the end means you want to start from your current directory, this could be substituted with any directory.
the -r means do this recursively, right down the directory tree
the -n prints the line number for matches.
the --include lets you add file names, extensions. Wildcards accepted
For more info see: http://www.gnu.org/software/grep/
Source: Stackoverflow.com