Find files containing a given text

Question

In bash I want to return file name  and the path to the file  for every file of type  php  html  js containing the case-insensitive string  document cookie     setcookie   How would I do that

User · Answer

find them and grep for the string   This will find all files of your 3 types in  starting path and grep for the regular expression   document  cookie setcookie     Split over 2 lines with the backslash just for readability     find  starting path -type f -name    php  -o -name    html  -o -name    js       xargs egrep -i   document  cookie setcookie

User · Answer

Try something like grep -r -n -i --include    html   php   js  searchstrinhere    the -i makes it case insensitlve  the   at the end means you want to start from your current directory  this could be substituted with any directory   the -r means do this recursively  right down the directory tree  the -n prints the line number for matches   the --include lets you add file names  extensions  Wildcards accepted   For more info see  http   www gnu org software grep

User · Answer

Just to include one more alternative  you could also use this   find   starting path  -type f -regextype posix-extended -regex        php html js    -exec grep -EH   document  cookie setcookie          Where    -regextype posix-extended tells find what kind of regex to expect -regex        php html js    tells find the regex itself filenames must match -exec grep -EH   document  cookie setcookie         tells find to run the command  with its options and arguments  specified between the -exec option and the    for each file it finds  where    represents where the file path goes in this command   while   E option tells grep to use extended regex  to support the parentheses  and    H option tells grep to print file paths before the matches     And  given this  if you only want file paths  you may use   find   starting path  -type f -regextype posix-extended -regex        php html js    -exec grep -EH   document  cookie setcookie           sed -r  s            1     sort -u  Where      pipe  send the output of find to the next command after this  which is sed  then sort   r option tells sed to use extended regex  s HI BYE  tells sed to replace every First occurrence  per line  of  HI  with  BYE  and    s            1  tells it to replace the regex            meaning a group  stuff enclosed by     including everything       one or more of any-character  from the beginning of the line     till  the first     followed by anything till  the end of line      by the first group   1  of the replaced regex  u tells sort to remove duplicate entries  take sort -u as optional        FAR from being the most elegant way  As I said  my intention is to increase the range of possibilities  and also to give more complete explanations on some tools you could use

User · Answer

Sounds like a perfect job for grep or perhaps ack  Or this wonderful construction   find   -type f    -name   php -o -name   html -o -name   js    -exec grep  document cookie  setcookie   dev null

User · Answer

find   -type f -name   php  -o -name   js  -o -name   html     xargs grep -liE  document  cookie setcookie

User · Answer

egrep -ir --include    php html js    document cookie setcookie       The r flag means to search recursively  search subdirectories   The i flag means case insensitive   If you just want file names add the l  lowercase L  flag   egrep -lir --include    php html js    document cookie setcookie

[bash] Find files containing a given text

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