Possible Duplicate:
save image from php url using php
I want to have PHP code for following.
Suppose I have one image URL, for example, http://www.google.co.in/intl/en_com/images/srpr/logo1w.png
If I run one script, this image will be copied and put on my server within folder having 777 rights.
Is it possible? If yea, can you please give direction for same?
Thanks,
Ian
This question is related to
php
$url = "http://www.example/images/image.gif";
$save_name = "image.gif";
$save_directory = "/var/www/example/downloads/";
if(is_writable($save_directory)) {
file_put_contents($save_directory . $save_name, file_get_contents($url));
} else {
exit("Failed to write to directory "{$save_directory}");
}
$url="http://www.google.co.in/intl/en_com/images/srpr/logo1w.png";
$contents=file_get_contents($url);
$save_path="/path/to/the/dir/and/image.jpg";
file_put_contents($save_path,$contents);
you must have allow_url_fopen
set to on
Two ways, if you're using PHP5 (or higher)
copy('http://www.google.co.in/intl/en_com/images/srpr/logo1w.png', '/tmp/file.png');
If not, use file_get_contents
//Get the file
$content = file_get_contents("http://www.google.co.in/intl/en_com/images/srpr/logo1w.png");
//Store in the filesystem.
$fp = fopen("/location/to/save/image.png", "w");
fwrite($fp, $content);
fclose($fp);
From this SO post
From Copy images from url to server, delete all images after
function getimg($url) {
$headers[] = 'Accept: image/gif, image/x-bitmap, image/jpeg, image/pjpeg';
$headers[] = 'Connection: Keep-Alive';
$headers[] = 'Content-type: application/x-www-form-urlencoded;charset=UTF-8';
$user_agent = 'php';
$process = curl_init($url);
curl_setopt($process, CURLOPT_HTTPHEADER, $headers);
curl_setopt($process, CURLOPT_HEADER, 0);
curl_setopt($process, CURLOPT_USERAGENT, $user_agent); //check here
curl_setopt($process, CURLOPT_TIMEOUT, 30);
curl_setopt($process, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($process, CURLOPT_FOLLOWLOCATION, 1);
$return = curl_exec($process);
curl_close($process);
return $return;
}
$imgurl = 'http://www.foodtest.ru/images/big_img/sausage_3.jpg';
$imagename= basename($imgurl);
if(file_exists('./tmp/'.$imagename)){continue;}
$image = getimg($imgurl);
file_put_contents('tmp/'.$imagename,$image);
This SO thread will solve your problem. Solution in short:
$url = 'http://www.google.co.in/intl/en_com/images/srpr/logo1w.png';
$img = '/my/folder/my_image.gif';
file_put_contents($img, file_get_contents($url));
Source: Stackoverflow.com