How to printf long long

Question

I m doing a program that aproximate PI and i m trying to use long long  but it isn t working  Here is the code   include lt stdio h gt   include lt math h gt  typedef long long num  main        num pi      pi 0      num e  n      scanf   d    amp n       for e 0  1 e           pi      pow  -1 0  e    2 0 e 1 0          if e n  0          printf   15lld - gt   1 16lld n  e  4 pi           printf   lld n  4 pi

User · Answer

Your scanf   statement needs to use  lld too  Your loop does not have a terminating condition  There are far too many parentheses and far too few spaces in the expression  pi    pow -1 0  e     2 0 e   1 0    You add one on the first iteration of the loop  and thereafter zero to the value of  pi   this does not change the value much  You should use an explicit return type of int for main    On the whole  it is best to specify int main void  when it ignores its arguments  though that is less of a categorical statement than the rest  I dislike the explicit licence granted in C99 to omit the return from the end of main   and don t use it myself  I write return 0  to be explicit    I think the whole algorithm is dubious when written using long long  the data type probably should be more like long double  with  Lf for the scanf   format  and maybe  19 16Lf for the printf   formats

User · Answer

acos 0 0  will return value of pi 2  inverse of cos 0  is pi 2      double pi   2   acos 0 0       int n     upto 6 digit     scanf   d   amp n     precision with which you want the value of pi     printf     lf n  n pi        will get replaced by n which is the required precision

User · Answer

First of all   d is for a int  So  1 16lld makes no sense  because  d is an integer  That typedef you do  is also unnecessary  use the type straight ahead  makes a much more readable code   What you want to use is the type double  for calculating pi and then using  f or  1 16f

User · Answer

lld is the standard C99 way  but that doesn t work on the compiler that I m using  mingw32-gcc v4 6 0   The way to do it on this compiler is   I64d  So try this   if e n  0 printf   15I64d - gt   1 16I64d n  e  4 pi     and  scanf   I64d    amp n     The only way I know of for doing this in a completely portable way is to use the defines in  lt inttypes h gt    In your case  it would look like this   scanf    SCNd64     amp n             if e n  0 printf   15 PRId64  - gt   1 16 PRId64  n  e  4 pi     It really is very ugly    but at least it is portable

[c] How to printf long long

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