Converting double to integer in Java

Question

In Java  I want to convert a double to an integer  I know if you do this   double x   1 5  int y    int x    you get y 1  If you do this   int y    int Math round x     You ll likely get 2  However  I am wondering  since double representations of integers sometimes look like 1 9999999998 or something  is there a possibility that casting a double created via Math round   will still result in a truncated down number  rather than the rounded number we are looking for  i e   1 instead of 2 in the code as represented      and yes  I do mean it as such  Is there any value for x  where y will show a result that is a truncated rather than a rounded representation of x    If so  Is there a better way to make a double into a rounded int without running the risk of truncation     Figured something  Math round x  returns a long  not a double  Hence  it is impossible for Math round   to return a number looking like 3 9999998  Therefore  int Math round    will never need to truncate anything and will always work

User · Accepted Answer

is there a possibility that casting a double created via Math.round() will still result in a truncated down number

No, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places. But after rounding, there will not be any fractional parts remaining.

Here are the docs from Math.round(double):

Returns the closest long to the argument. The result is rounded to an integer by adding 1/2, taking the floor of the result, and casting the result to type long. In other words, the result is equal to the value of the expression:
(long)Math.floor(a + 0.5d)

User · Answer

For the datatype Double to int  you can use the following   Double double   5 00   int integer   double intValue

User · Answer

Double perValue   96 57  int roundVal   int  Math round perValue     Solved my purpose

[java] Converting double to integer in Java

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