If statement for strings in python

Question

I am a total beginner and have been looking at http   en wikibooks org wiki Python Programming Conditional Statements but I can not understand the problem here  It is pretty simple  if the user enters y it should print this will do the calculation although I get a syntax error on IF answer   y   answer   str input  Is the information correct  Enter Y for yes or N for no    proceed  y  or  Y   If answer  proceed  print  this will do the calculation    else  exit

User · Answer

proceed    y    Y  if answer in proceed    Also  you don t want  answer   str input  Is the information correct  Enter Y for yes or N for no      You want   answer   raw input  Is the information correct  Enter Y for yes or N for no     input   evaluates whatever is entered as a Python expression  raw input   returns a string   Edit  That is only true on Python 2  On Python 3  input is fine  although str   wrapping is still redundant

User · Answer

Python is a case-sensitive language  All Python keywords are lowercase  Use if  not If   Also  don t put a colon after the call to print    Also  indent the print   and exit   calls  as Python uses indentation rather than brackets to represent code blocks   And also  proceed    y  or  Y  won t do what you want  Use proceed    y  and if answer lower      proceed   or something similar   There s also the fact that your program will exit as long as the input value is not the single character  y  or  Y   which contradicts the prompting of  N  for the alternate case  Instead of your else clause there  use elif answer lower      info incorrect   with info incorrect    n  somewhere beforehand  Then just reprompt for the response or something if the input value was something else     I d recommend going through the tutorial in the Python documentation if you re having this much trouble the way you re learning now  http   docs python org tutorial index html

User · Answer

If should be if  Your program should look like this   answer   raw input  Is the information correct  Enter Y for yes or N for no   if answer upper       Y       print  this will do the calculation   else      exit     Note also that the indentation is important  because it marks a block in Python

User · Answer

You want   answer   str raw input  Is the information correct  Enter Y for yes or N for no    if answer     y  or answer     Y     print  this will do the calculation   else    exit     Or  answer   str raw input  Is the information correct  Enter Y for yes or N for no    if answer in   y   Y      print  this will do the calculation   else    exit     Note    It s  if   not  If   Python is case sensitive  Indentation is important  There is no colon or semi-colon at the end of python commands  You want raw input not input  input evals the input   or  gives you the first result if it evaluates to true  and the second result otherwise  So  a  or  b  evaluates to  a   whereas 0 or  b  evaluates to  b   See The Peculiar Nature of and and or

User · Answer

Even once you fixed the mis-cased if and improper indentation in your code  it wouldn t work as you probably expected   To check a string against a set of strings  use in   Here s how you d do it  and note that if is all lowercase and that the code within the if block is indented one level    One approach   if answer in   y    Y    yes    Yes    YES        print  this will do the calculation     Another   if answer lower   in   y    yes        print  this will do the calculation

User · Answer

Python is case sensitive and needs proper indentation  You need to use lowercase  if   indent your conditions properly and the code has a bug  proceed will evaluate to y

[python] If statement for strings in python?

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