How to remove all duplicate items from a list

Question

How would I use python to check a list and delete all duplicates  I don t want to have to specify what the duplicate item is - I want the code to figure out if there are any and remove them if so  keeping only one instance of each  It also must work if there are multiple duplicates in a list    For example  in my code below  the list lseparatedOrbList has 12 items - one is repeated six times  one is repeated five times  and there is only one instance of one  I want it to change the list so there are only three items - one of each  and in the same order they appeared before  I tried this   for i in lseparatedOrbList     for j in lseparatedOrblist          if lseparatedOrbList i     lseparatedOrbList j               lseparatedOrbList remove lseparatedOrbList j     But I get the error   Traceback  most recent call last     File  qchemOutputSearch py   line 123  in  lt module gt      for j in lseparatedOrblist  NameError  name  lseparatedOrblist  is not defined   I m guessing because it s because I m trying to loop through lseparatedOrbList while I loop through it  but I can t think of another way to do it

User · Answer

It s because you are missing a capital letter  actually   Purposely dedented   for i in lseparatedOrbList      capital  L  for j in lseparatedOrblist      lowercase  l    Though the more efficient way to do it would be to insert the contents into a set   If maintaining the list order matters  ie  it must be  stable    check out the answers on this question

User · Answer

for unhashable lists  It is faster as it does not iterate about already checked entries   def purge dublicates X       unique X          for i  row in enumerate X           if row not in X i   1                unique X append row      return unique X

User · Answer

Just make a new list to populate  if the item for your list is not yet in the new list input it  else just move on to the next item in your original list   for i in mylist    if i not in newlist      newlist append i    I think this is the correct syntax  but my python is a bit shaky  I hope you at least get the idea

User · Answer

There is a faster way to fix this   list    1  1 0  1 41  1 73  2  2  2 0  2 24  3  3  4  4  4  5  6  6  8  8  9  10  list2     for value in list      try          list2 index value      except          list2 append value  list clear   for value in list2      list append value  list2 clear   print list  print list2

User · Answer

You can do this like that   x   list set x     Example  if you do something like that   x    1 2 3 4 5 6 7 8 9 10 2 1 6 31 20  x   list set x   x   you will see the following result    1  2  3  4  5  6  7  8  9  10  20  31    There is only one thing you should think of  the resulting list will not be ordered as the original one  will lose the order in the process

User · Answer

This should be faster and will preserve the original order   seen      new list    seen setdefault x  x  for x in my list if x not in seen    If you don t care about order  you can just   new list   list set my list

User · Answer

This should do it for you   new list   list set old list     set will automatically remove duplicates  list will cast it back to a list

User · Answer

In this way one can delete a particular item which is present multiple times in a list   Try deleting all 5  list1  1 2 3 4 5 6 5 3 5 7 11 5 9 8 121 98 67 34 5 21  print list1 n input  item to be deleted       for i in list1      if n in list1          list1 remove n  print list1

User · Answer

Use set     woduplicates   set lseparatedOrblist    Returns a set without duplicates  If you  for some reason  need a list back   woduplicates   list set lseperatedOrblist     This will  however  have a different order than your original list

User · Answer

The modern way to do it that maintains the order is    gt  gt  gt  from collections import OrderedDict  gt  gt  gt  list OrderedDict fromkeys lseparatedOrbList     as discussed by Raymond Hettinger  python core dev  in this answer  In python 3 5 and above this is also the fastest way - see the linked answer for details  However the keys must be hashable  as is the case in your list I think

User · Answer

No  it s simply a typo  the  list  at the end must be capitalized  You can nest loops over the same variable just fine  although there s rarely a good reason to    However  there are other problems with the code  For starters  you re iterating through lists  so i and j will be items not indices  Furthermore  you can t change a collection while iterating over it  well  you  can  in that it runs  but madness lies that way - for instance  you ll propably skip over items   And then there s the complexity problem  your code is O n 2   Either convert the list into a set and back into a list  simple  but shuffles the remaining list items  or do something like this   seen   set   new x      for x in xs      if x in seen          continue     seen add x      new xs append x    Both solutions require the items to be hashable  If that s not possible  you ll probably have to stick with your current approach sans the mentioned problems

[python] How to remove all duplicate items from a list

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