How to remove specific element from an array using python

Question

I want to write something that removes a specific element from an array  I know that I have to for loop through the array to find the element that matches the content    Let s say that I have an array of emails and I want to get rid of the element that matches some email string   I d actually like to use the for loop structure because I need to use the same index for other arrays as well    Here is the code that I have   for index  item in emails      if emails index      something something com            emails pop index           otherarray pop index

User · Answer

Your for loop is not right  if you need the index in the for loop use   for index  item in enumerate emails         whatever  but you can t remove element while iterating    In your case  Bogdan solution is ok  but your data structure choice is not so good  Having to maintain these two lists with data from one related to data from the other at same index is clumsy   A list of tupple  email  otherdata  may be better  or a dict with email as key

User · Answer

Using filter   and lambda would provide a neat and terse method of removing unwanted values   newEmails   list filter lambda x   x     something something com   emails     This does not modify emails  It creates the new list newEmails containing only elements for which the anonymous function returned True

User · Answer

If you want to delete the index of array  Use array name pop index no   ex -  gt  gt  gt  arr    1 2 3 4   gt  gt  gt  arr pop 2   gt  gt  gt arr  1 2 4   If you want to delete a particular string element from the array then  gt  gt  gt  arr1     python3 6     python2    python3    gt  gt  gt  arr1 remove  python2    gt  gt  gt  arr1   python3 6   python3

User · Answer

There is an alternative solution to this problem which also deals with duplicate matches   We start with 2 lists of equal length  emails  otherarray  The objective is to remove items from both lists for each index i where emails i      something something com    This can be achieved using a list comprehension and then splitting via zip   emails     abc def com    something something com    ghi jkl com   otherarray     some    other    details    from operator import itemgetter  res     i  j  for i  j in zip emails  otherarray  if i    something something com   emails  otherarray   map list  map itemgetter 0  1   zip  res     print emails           abc def com    ghi jkl com   print otherarray       some    details

User · Answer

You don t need to iterate the array  Just    gt  gt  gt  x     ala ala com    bala bala com    gt  gt  gt  x   ala ala com    bala bala com    gt  gt  gt  x remove  ala ala com    gt  gt  gt  x   bala bala com     This will remove the first occurence that matches the string   EDIT  After your edit  you still don t need to iterate over  Just do   index   initial list index item1  del initial list index  del other list index

User · Answer

The sane way to do this is to use zip   and a List Comprehension   Generator Expression   filtered          email  other           for email  other in zip emails  other list               if email     something something com    new emails  new other list   zip  filtered    Also  if your e not using array array   or numpy array    then most likely you are using    or list    which give you Lists  not Arrays  Not the same thing

[python] How to remove specific element from an array using python

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