[bash] bash: shortest way to get n-th column of output

Because you seem to be unfamiliar with scripts, here is an example.

#!/bin/sh
# usage: svn st | x 2 | xargs rm
col=$1
shift
awk -v col="$col" '{print $col}' "${@--}"

If you save this in ~/bin/x and make sure ~/bin is in your PATH (now that is something you can and should put in your .bashrc) you have the shortest possible command for generally extracting column n; x n.

The script should do proper error checking and bail if invoked with a non-numeric argument or the incorrect number of arguments, etc; but expanding on this bare-bones essential version will be in unit 102.

Maybe you will want to extend the script to allow a different column delimiter. Awk by default parses input into fields on whitespace; to use a different delimiter, use -F ':' where : is the new delimiter. Implementing this as an option to the script makes it slightly longer, so I'm leaving that as an exercise for the reader.


Usage

Given a file file:

1 2 3
4 5 6

You can either pass it via stdin (using a useless cat merely as a placeholder for something more useful);

$ cat file | sh script.sh 2
2
5

Or provide it as an argument to the script:

$ sh script.sh 2 file
2
5

Here, sh script.sh is assuming that the script is saved as script.sh in the current directory; if you save it with a more useful name somewhere in your PATH and mark it executable, as in the instructions above, obviously use the useful name instead (and no sh).