Is there any built-in method in Java which allows us to convert comma separated String to some container (e.g array, List or Vector)? Or do I need to write custom code for that?
String commaSeparated = "item1 , item2 , item3";
List<String> items = //method that converts above string into list??
This question is related to
java
string
collections
split
While this question is old and has been answered multiple times, none of the answers is able to manage the all of the following cases:
""
-> empty string should be mapped to empty list" a, b , c "
-> all elements should be trimmed, including the first and last element",,"
-> empty elements should be removedThus, I'm using the following code (using org.apache.commons.lang3.StringUtils
, e.g. https://mvnrepository.com/artifact/org.apache.commons/commons-lang3/3.11):
StringUtils.isBlank(commaSeparatedEmailList) ?
Collections.emptyList() :
Stream.of(StringUtils.split(commaSeparatedEmailList, ','))
.map(String::trim)
.filter(StringUtils::isNotBlank)
.collect(Collectors.toList());
Using a simple split expression has an advantage: no regular expression is used, so the performance is probably higher. The commons-lang3
library is lightweight and very common.
Note that the implementation assumes that you don't have list element containing comma (i.e. "a, 'b,c', d"
will be parsed as ["a", "'b", "c'", "d"]
, not to ["a", "b,c", "d"]
).
There is no built-in method for this but you can simply use split() method in this.
String commaSeparated = "item1 , item2 , item3";
ArrayList<String> items =
new ArrayList<String>(Arrays.asList(commaSeparated.split(",")));
An example using Collections
.
import java.util.Collections;
...
String commaSeparated = "item1 , item2 , item3";
ArrayList<String> items = new ArrayList<>();
Collections.addAll(items, commaSeparated.split("\\s*,\\s*"));
...
In Kotlin if your String list like this and you can use for convert string to ArrayList use this line of code
var str= "item1, item2, item3, item4"
var itemsList = str.split(", ")
You can first split them using String.split(",")
, and then convert the returned String array
to an ArrayList
using Arrays.asList(array)
I usually use precompiled pattern for the list. And also this is slightly more universal since it can consider brackets which follows some of the listToString expressions.
private static final Pattern listAsString = Pattern.compile("^\\[?([^\\[\\]]*)\\]?$");
private List<String> getList(String value) {
Matcher matcher = listAsString.matcher((String) value);
if (matcher.matches()) {
String[] split = matcher.group(matcher.groupCount()).split("\\s*,\\s*");
return new ArrayList<>(Arrays.asList(split));
}
return Collections.emptyList();
This code will help,
String myStr = "item1,item2,item3";
List myList = Arrays.asList(myStr.split(","));
Two steps:
String [] items = commaSeparated.split("\\s*,\\s*");
List<String> container = Arrays.asList(items);
convert Collection into string as comma seperated in Java 8
listOfString object contains ["A","B","C" ,"D"] elements-
listOfString.stream().map(ele->"'"+ele+"'").collect(Collectors.joining(","))
Output is :- 'A','B','C','D'
And Convert Strings Array to List in Java 8
String string[] ={"A","B","C","D"};
List<String> listOfString = Stream.of(string).collect(Collectors.toList());
you can combine asList and split
Arrays.asList(CommaSeparated.split("\\s*,\\s*"))
ArrayList<HashMap<String, String>> mListmain = new ArrayList<HashMap<String, String>>();
String marray[]= mListmain.split(",");
You can do it as follows.
This removes white space and split by comma where you do not need to worry about white spaces.
String myString= "A, B, C, D";
//Remove whitespace and split by comma
List<String> finalString= Arrays.asList(myString.split("\\s*,\\s*"));
System.out.println(finalString);
Arrays.asList
returns a fixed-size List
backed by the array. If you want a normal mutable java.util.ArrayList
you need to do this:
List<String> list = new ArrayList<String>(Arrays.asList(string.split(" , ")));
Or, using Guava:
List<String> list = Lists.newArrayList(Splitter.on(" , ").split(string));
Using a Splitter
gives you more flexibility in how you split the string and gives you the ability to, for example, skip empty strings in the results and trim results. It also has less weird behavior than String.split
as well as not requiring you to split by regex (that's just one option).
Here is another one for converting CSV to ArrayList:
String str="string,with,comma";
ArrayList aList= new ArrayList(Arrays.asList(str.split(",")));
for(int i=0;i<aList.size();i++)
{
System.out.println(" -->"+aList.get(i));
}
Prints you
-->string
-->with
-->comma
List<String> items = Arrays.asList(commaSeparated.split(","));
That should work for you.
List<String> items = Arrays.asList(s.split("[,\\s]+"));
You can use Guava to split the string, and convert it into an ArrayList. This works with an empty string as well, and returns an empty list.
import com.google.common.base.Splitter;
import com.google.common.collect.Lists;
String commaSeparated = "item1 , item2 , item3";
// Split string into list, trimming each item and removing empty items
ArrayList<String> list = Lists.newArrayList(Splitter.on(',').trimResults().omitEmptyStrings().splitToList(commaSeparated));
System.out.println(list);
list.add("another item");
System.out.println(list);
outputs the following:
[item1, item2, item3]
[item1, item2, item3, another item]
List<String> items= Stream.of(commaSeparated.split(","))
.map(String::trim)
.collect(toList());
Same result you can achieve using the Splitter class.
var list = Splitter.on(",").splitToList(YourStringVariable)
(written in kotlin)
In groovy, you can use tokenize(Character Token) method:
list = str.tokenize(',')
String -> Collection conversion: (String -> String[] -> Collection)
// java version 8
String str = "aa,bb,cc,dd,aa,ss,bb,ee,aa,zz,dd,ff,hh";
// Collection,
// Set , List,
// HashSet , ArrayList ...
// (____________________________)
// || ||
// \/ \/
Collection<String> col = new HashSet<>(Stream.of(str.split(",")).collect(Collectors.toList()));
Collection -> String[] conversion:
String[] se = col.toArray(new String[col.size()]);
String -> String[] conversion:
String[] strArr = str.split(",");
And Collection -> Collection:
List<String> list = new LinkedList<>(col);
There are many ways to solve this using streams in Java 8 but IMO the following one liners are straight forward:
String commaSeparated = "item1 , item2 , item3";
List<String> result1 = Arrays.stream(commaSeparated.split(" , "))
.collect(Collectors.toList());
List<String> result2 = Stream.of(commaSeparated.split(" , "))
.collect(Collectors.toList());
If a List
is the end-goal as the OP stated, then already accepted answer is still the shortest and the best. However I want to provide alternatives using Java 8 Streams, that will give you more benefit if it is part of a pipeline for further processing.
By wrapping the result of the .split function (a native array) into a stream and then converting to a list.
List<String> list =
Stream.of("a,b,c".split(","))
.collect(Collectors.toList());
If it is important that the result is stored as an ArrayList
as per the title from the OP, you can use a different Collector
method:
ArrayList<String> list =
Stream.of("a,b,c".split(","))
.collect(Collectors.toCollection(ArrayList<String>::new));
Or by using the RegEx parsing api:
ArrayList<String> list =
Pattern.compile(",")
.splitAsStream("a,b,c")
.collect(Collectors.toCollection(ArrayList<String>::new));
Note that you could still consider to leave the list
variable typed as List<String>
instead of ArrayList<String>
. The generic interface for List
still looks plenty of similar enough to the ArrayList
implementation.
By themselves, these code examples do not seem to add a lot (except more typing), but if you are planning to do more, like this answer on converting a String to a List of Longs exemplifies, the streaming API is really powerful by allowing to pipeline your operations one after the other.
For the sake of, you know, completeness.
List commaseperated = new ArrayList();
String mylist = "item1 , item2 , item3";
mylist = Arrays.asList(myStr.trim().split(" , "));
// enter code here
Source: Stackoverflow.com