I get the following error
Warning: mysqli_error() expects exactly 1 parameter, 0 given
The problem is with this line of the code:
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error());
The whole code is
session_start();
require_once "scripts/connect_to_mysql2.php";
//Build Main Navigation menu and gather page data here
$sqlCommand = "SELECT id, linklabel FROM pages ORDER BY pageorder ASC";
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error());
$menuDisplay = '';
while ($row = mysqli_fetch_array($query)) {
$pid = $row["id"];
$linklabel = $row["linklabel"];
$menuDisplay .= '<a href="index.php?pid=' . $pid . '">' . $linklabel . '</a><br />';
}
mysqli_free_result($query);
The included file has the following line
$myConnection = mysqli_connect("$db_host","$db_username","$db_pass","$db_name") or die ("could not connect to mysql"); with reference to $myConnection, why do I get this error?
At first, the problem is because you did't put any parameter for mysqli_error. I can see that it has been solved based on the post here. Most probably, the next problem is cause by wrong file path for the included file.. .
Are you sure this code
$myConnection = mysqli_connect("$db_host","$db_username","$db_pass","$db_name") or die ("could not connect to mysql");
is in the 'scripts' folder and your main code file is on the same level as the script folder?
Change
die (mysqli_error());
to
die('Error: ' . mysqli_error($myConnection));
in the query
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error());
mysqli_error
function requires $myConnection
as parameters, that's why you get the warning
Source: Stackoverflow.com