Subtract 1 day with PHP

Question

I m trying to take a date object that s coming out of my Drupal CMS  subtract one day and print out both dates   Here s what I have   date raw    messagenode- gt field message date 0   value     print  date raw      this gives me the following string  2011-04-24T00 00 00   date object   date create  date raw     next date object   date modify  date object  -1 day     print  First Date     date format  date object  Y-m-d        this gives me the correctly formatted string  2011-04-24   print  Next Date     date format  next date object  Y-m-d        this gives me nothing  The output here is always blank   So I m not understanding why the original date object is coming out fine  but then I m trying to create an additional date object and modify it by subtracting one day and it seems like I can t do that   The output always comes out blank

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How to add 1 year to a date and then subtract 1 day from it in asp net c   Convert ToDateTime txtDate Value Trim    AddYears 1  AddDays -1

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You can try   print  Next Date     date  Y-m-d   strtotime  -1 day   strtotime  date raw

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date  Y-m-d   strtotime    -1 day    strtotime    date

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Object oriented version   dateObject   new DateTime   date raw    print  Next Date      dateObject- gt sub  new DateInterval  P1D    - gt format  Y-m-d

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Answear taken from Php manual strtotime function comments    echo date   Y-m-d   strtotime   2009-01-31 -1 day       Or    date    2009-01-31   echo date   Y-m-d   strtotime   date    -1 day

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date   new DateTime  2017-05-18       For today now  don t pass an arg   date- gt modify  -1 day    echo  date- gt format  Y-m-d H i s      Using DateTime has significantly reduced the amount of headaches endured whilst manipulating dates

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How about this  convert it to a unix timestamp first  subtract 60 60 24  exactly one day in seconds   and then grab the date from that    newDate   strtotime  date raw  - 60 60 24  echo date  Y-m-d   newDate     Note  as  apokryfos has pointed out  this would technically be thrown off by daylight savings time changes where there would be a day with either 25 or 23 hours

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Not sure why your current code isn t working but if you don t specifically need a date object this will work    first date   strtotime  date raw    second date   strtotime  -1 day    first date    print  First Date     date  Y-m-d    first date   print  Next Date     date  Y-m-d    second date

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A one-liner option is   echo date create  2011-04-24  - gt modify  -1 days  - gt format  Y-m-d      Running it on Online PHP Editor    mktime alternative  If you prefer to avoid using string methods  or going into calculations  or even creating additional variables  mktime supports subtraction and negative values in the following way      Today s date echo date  Y-m-d       2016-03-22     Yesterday s date echo date  Y-m-d   mktime 0  0  0  date  m    date  d  -1  date  Y         2016-03-21     42 days ago echo date  Y-m-d   mktime 0  0  0  date  m    date  d  -42  date  Y         2016-02-09    Using a previous date object  date object   new DateTime  2011-04-24    echo date  Y-m-d     mktime 0  0  0        date object- gt format  m          date object- gt format  d  -1        date object- gt format  Y               2011-04-23   Online PHP Editor

User · Answer

Simple like that   date  Y-m-d   strtotime  -1 day      date  Y-m-d   strtotime  -1 months

[php] Subtract 1 day with PHP

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