How to test valid UUID GUID

Question

How to check if variable contains valid UUID GUID identifier   I m currently interested only in validating types 1 and 4  but it should not be a limitation to your answers

User · Accepted Answer

Currently  UUID s are as specified in RFC4122  An often neglected edge case is the NIL UUID  noted here  The following regex takes this into account and will return a match for a NIL UUID  See below for a UUID which only accepts non-NIL UUIDs  Both of these solutions are for versions 1 to 5  see the first character of the third block    Therefore to validate a UUID        0-9a-f  8 - 0-9a-f  4 - 0-5  0-9a-f  3 - 089ab  0-9a-f  3 - 0-9a-f  12   i      ensures you have a canonically formatted UUID that is Version 1 through 5 and is the appropriate Variant as per RFC4122   NOTE  Braces   and   are not canonical  They are an artifact of some systems and usages   Easy to modify the above regex to meet the requirements of the original question   HINT  regex group captures  To avoid matching NIL UUID      0-9a-f  8 - 0-9a-f  4 - 1-5  0-9a-f  3 - 89ab  0-9a-f  3 - 0-9a-f  12   i

User · Answer

Use the  match   method to check whether String is UUID   public boolean isUUID String s       return s match    0-9a-fA-F  8 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  12

User · Answer

A good way to do it in Node is to use the ajv package  https   github com epoberezkin ajv   const Ajv   require  ajv    const ajv   new Ajv   allErrors  true  useDefaults  true  verbose  true     const uuidSchema     type   string   format   uuid     ajv validate uuidSchema   bogus       returns false ajv validate uuidSchema   d42a8273-a4fe-4eb2-b4ee-c1fc57eb9865       returns true with v4 GUID ajv validate uuidSchema   892717ce-3bd8-11ea-b77f-2e728ce88125       returns true with a v1 GUID

User · Answer

If you are using Node js for development  it is recommended to use a package called Validator  It includes all the regexes required to validate different versions of UUID s plus you get various other functions for validation   Here is the npm link  Validator  var a    d3aa88e2-c754-41e0-8ba6-4198a34aa0a2  v isUUID a  true v isUUID  abc   false v isNull a  false

User · Answer

A slightly modified version of the above answers written in a more concise way  This will validate any GUID with hyphens  however easily modified to make hyphens optional   This will also support upper and lower case characters which has become the convention regardless of the specification       0-9a-fA-F  8  -   0-9a-fA-F  4  -  3    0-9a-fA-F  12    i   The key here is the repeating part below     0-9a-fA-F  4  -  3     Which simply repeats the 4 char patterns 3 times

User · Answer

thanks to  usertatha with some modification  function isUUID   uuid         let s        uuid       s   s match    0-9a-fA-F  8 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  12          if  s     null          return false            return true

User · Answer

I think Gambol s answer is almost perfect  but it misinterprets the RFC 4122    4 1 1  Variant section a bit   It covers Variant-1 UUIDs  10xx   8  b   but does not cover Variant-0  0xxx   0  7  and Variant-2  110x   c  d  variants which are reserved for backward compatibility  so they are technically valid UUIDs  Variant-4  111x   e  f  is indeed reserved for future use  so they are not valid currently   Also  0 type is not valid  that  digit  is only allowed to be 0 if it s a NIL UUID  like mentioned in Evan s answer    So I think the most accurate regex that complies with current RFC 4122 specification is  including hyphens        0-9a-f  8 - 0-9a-f  4 - 1-5  0-9a-f  3 - 0-9a-d  0-9a-f  3 - 0-9a-f  12  00000000-0000-0000-0000-000000000000   i                                                                          0 type is not valid    only e  f variant digit is invalid currently

User · Answer

regex to the rescue     0-9a-fA-F  8 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  12    test  01234567-9ABC-DEF0-1234-56789ABCDEF0      or with brackets        0-9a-fA-F  8 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  4 - 0-9a-fA-F  12

User · Answer

Beside Gambol s answer that will do the job in nearly all cases  all answers given so far missed that the grouped formatting  8-4-4-4-12  is not mandatory to encode GUIDs in text  It s used extremely often but obviously also a plain chain of 32 hexadecimal digits can be valid  1  regexenh      0-9a-f  8 -  0-9a-f  4 -  1-5  0-9a-f  3 -  89ab  0-9a-f  3 -  0-9a-f  12   i      1  The question is about checking variables  so we should include the user-unfriendly form as well    Why are there dashes in a  NET GUID  - Stack Overflow plus Accepted answer Test and validate a GUID  guid us  Guid ToString Method  String   MSDN

User · Answer

If you want to check or validate a specific UUID version  here are the corresponding regexes      Note that the only difference is the version number  which is explained in 4 1 3  Version chapter of UUID 4122 RFC    The version number is the first character of the third group    VERSION NUMBER  0-9A-F  3      UUID v1       0-9A-F  8 - 0-9A-F  4 - 1  0-9A-F  3 - 89AB  0-9A-F  3 - 0-9A-F  12   i  UUID v2       0-9A-F  8 - 0-9A-F  4 - 2  0-9A-F  3 - 89AB  0-9A-F  3 - 0-9A-F  12   i  UUID v3       0-9A-F  8 - 0-9A-F  4 - 3  0-9A-F  3 - 89AB  0-9A-F  3 - 0-9A-F  12   i  UUID v4       0-9A-F  8 - 0-9A-F  4 - 4  0-9A-F  3 - 89AB  0-9A-F  3 - 0-9A-F  12   i  UUID v5       0-9A-F  8 - 0-9A-F  4 - 5  0-9A-F  3 - 89AB  0-9A-F  3 - 0-9A-F  12   i

User · Answer

I think a better way is using the static method fromString to avoid those regular expressions        id   UUID randomUUID        UUID uuid   UUID fromString id toString         Assert assertEquals id toString    uuid toString       On the other hand      UUID uuidFalse   UUID fromString  x      throws java lang IllegalArgumentException  Invalid UUID string  x

User · Answer

All type-specific regexes posted so far are failing on the  type 0  Nil UUID  defined in 4 1 7 of the RFC as      The nil UUID is special form of UUID that is specified to have all 128 bits set to zero  00000000-0000-0000-0000-000000000000   To modify Wolf s answer      0-9a-f  8 -  0-9a-f  4 -  0-5  0-9a-f  3 -  089ab  0-9a-f  3 -  0-9a-f  12   i   Or  to properly exclude a  type 0  without all zeros  we have the following  thanks to Luke          0-9a-f  8 -  0-9a-f  4 -  1-5  0-9a-f  3 -  89ab  0-9a  -f  3 -  0-9a-f  12    00000000-0000-0000-  0000-000000000000     i

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