Difference between two dates in Python

Question

I have two different dates and I want to know the difference in days between them  The format of the date is YYYY-MM-DD   I have a function that can ADD or SUBTRACT a given number to a date   def addonDays a  x      ret   time strftime   Y- m- d  time localtime time mktime time strptime a   Y- m- d    x 3600 24 3600            return ret   where A is the date and x the number of days I want to add  And the result is another date   I need a function where I can give two dates and the result would be an int with date difference in days

User · Answer

I tried a couple of codes  but end up using something as simple as  in Python 3   from datetime import datetime df  difference in datetime     abs df  end datetime   - df  start datetime     If your start datetime and end datetime columns are in datetime64 ns  format  datetime understands it and return the difference in days   timestamp  which is in timedelta64 ns  format  If you want to see only the difference in days  you can separate only the date portion of the start datetime and end datetime by using  also works for the time portion   df  start date     df  start datetime   dt date df  end date     df  end datetime   dt date  And then run  df  difference in days     abs df  end date   - df  start date

User · Answer

Use - to get the difference between two datetime objects and take the days member   from datetime import datetime  def days between d1  d2       d1   datetime strptime d1    Y- m- d       d2   datetime strptime d2    Y- m- d       return abs  d2 - d1  days

User · Answer

Try this   data pd read csv  C  Users Desktop Data Exploration csv   data head 5  first data  1st Gift   last data  Last Gift   maxi data  Largest Gift   l 1 np mean first -3 np std first  u 1 np mean first  3 np std first    m np abs data  1st Gift  -np mean data  1st Gift     gt 3 np std data  1st Gift    pd value counts m  l first m  data loc    1st Gift   m  True  np mean data  1st Gift    3 np std data  1st Gift    data  1st Gift   head       m np abs data  Last Gift  -np mean data  Last Gift     gt 3 np std data  Last Gift    pd value counts m  l last m  data loc    Last Gift   m  True  np mean data  Last Gift    3 np std data  Last Gift    data  Last Gift   head

User · Answer

pd date range  2019-01-01    2019-02-01   shape 0

User · Answer

I tried the code posted by larsmans above but  there are a couple of problems   1  The code as is will throw the error as mentioned by mauguerra 2  If you change the code to the following           d1   d1 strftime   Y- m- d       d2   d2 strftime   Y- m- d       return abs  d2 - d1  days    This will convert your datetime objects to strings but  two things  1  Trying to do d2 - d1 will fail as you cannot use the minus operator on strings and 2  If you read the first line of the above answer it stated  you want to use the - operator on two datetime objects but  you just converted them to strings  What I found is that you literally only need the following   import datetime  end date   datetime datetime utcnow   start date   end date - datetime timedelta days 8  difference in days   abs  end date - start date  days   print difference in days

User · Answer

Another short solution   from datetime import date  def diff dates date1  date2       return abs date2-date1  days  def main        d1   date 2013 1 1      d2   date 2013 9 13      result1   diff dates d2  d1      print     days between    and     format result1  d1  d2      print   Happy programmer s day     main

[python] Difference between two dates in Python

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