[mysql] Using an IF Statement in a MySQL SELECT query

I am trying to use an IF statement in a MySQL select query.

I am getting an error after the AND statement where the first IF.

SELECT J.JOB_ID,E.COMPANY_NAME,J.JOB_DESC,JT.JOBTYPE_NAME,J.COMPENSATION,ST.STATE_NAME,MC.METRO_CITY_NAME,I.INDUSTRY_NAME,
 J.JOB_CONTACT_PERSON,J.DT_INSRT,J.JOB_TITLE,J.JOB_EXP_DATE,J.SKILLS
 FROM JOBS J 
 JOIN EMPLOYER E ON J.COMPANY_ID=E.COMPANY_ID 
 JOIN LOOKUP_JOBTYPE JT ON J.JOB_TYPE=JT.JOBTYPE_ID
 JOIN LOOKUP_STATE ST ON J.STATE_ID=ST.STATE_ID
 JOIN JOBS_LOCATION JL ON J.JOB_ID=JL.JOB_ID
 JOIN LOOKUP_METRO_CITY MC ON JL.METRO_CITY_ID=MC.METRO_CITY_ID
 JOIN LOOKUP_INDUSTRY I ON J.INDUSTRY_ID=I.INDUSTRY_ID 
 JOIN JOBS_QUALIFICATION JQ ON J.JOB_ID=JQ.JOB_ID 
 JOIN LOOKUP_DEGREE_QUALIFICATION LDQ ON LDQ.QUALIFICATION_ID = JQ.QUALIFICATION_ID
 WHERE  J.ACTIVE='Y' AND J.DT_INSRT > COALESCE(pEmailSntDt,DATE_SUB(SYSDATE(),INTERVAL 4 DAY))  
AND
IF(JQ.COURSE_ID=0) 
THEN
IF(JQ.DEGREE_ID=0)
THEN J.SKILLS LIKE CONCAT('%', pSkills,'%')
ELSE
JQ.DEGREE_ID=pDegreeId OR J.SKILLS LIKE CONCAT('%', pSkills,'%')
END IF
ELSE
JQ.COURSE_ID=pCourseId OR IF(JQ.DEGREE_ID=0)
                      THEN
                      J.SKILLS LIKE CONCAT('%', pSkills,'%')
                      ELSE
                      JQ.DEGREE_ID=pDegreeId OR J.SKILLS LIKE CONCAT('%', pSkills,'%')
                      END IF
END IF                           
GROUP BY J.JOB_ID ORDER BY J.DT_INSRT DESC;

Why doesn't this work and what is the proper way to do an IF statement in a MySQL query?

How to use an IF statement in the MySQL "select list":

select if (1>2, 2, 3);                         //returns 3
select if(1<2,'yes','no');                     //returns yes
SELECT IF(STRCMP('test','test1'),'no','yes');  //returns no

How to use an IF statement in the MySQL where clause search condition list:

create table penguins (id int primary key auto_increment, name varchar(100))
insert into penguins (name) values ('rico')
insert into penguins (name) values ('kowalski')
insert into penguins (name) values ('skipper')

select * from penguins where 3 = id
-->3    skipper

select * from penguins where (if (true, 2, 3)) = id
-->2    kowalski

How to use an IF statement in the MySQL "having clause search conditions":

select * from penguins 
where 1=1
having (if (true, 2, 3)) = id
-->1    rico

Use an IF statement with a column used in the select list to make a decision:

select (if (id = 2, -1, 1)) item
from penguins
where 1=1
--> 1
--> -1
--> 1

If statements embedded in SQL queries is a bad "code smell". Bad code has high "WTF's per minute" during code review. This is one of those things. If I see this in production with your name on it, I'm going to automatically not like you.

try this code worked for me

SELECT user_display_image AS user_image,
       user_display_name AS user_name,
       invitee_phone,
       (CASE WHEN invitee_status = 1 THEN "attending"
             WHEN invitee_status = 2 THEN "unsure"
             WHEN invitee_status = 3 THEN "declined"
             WHEN invitee_status = 0 THEN "notreviwed"
       END) AS invitee_status
  FROM your_table