[c#] Returning a stream from File.OpenRead()

Options:

  • Use data.Seek as suggested by ken2k
  • Use the somewhat simpler Position property:

    data.Position = 0;
    
  • Use the ToArray call in MemoryStream to make your life simpler to start with:

    byte[] buf = data.ToArray();
    

The third option would be my preferred approach.

Note that you should have a using statement to close the file stream automatically (and optionally for the MemoryStream), and I'd add a using directive for System.IO to make your code cleaner:

byte[] buf;
using (MemoryStream data = new MemoryStream())
{
    using (Stream file = TestStream())
    {
        file.CopyTo(data);
        buf = data.ToArray();
    }
}

// Use buf

You might also want to create an extension method on Stream to do this for you in one place, e.g.

public static byte[] CopyToArray(this Stream input)
{
    using (MemoryStream memoryStream = new MemoryStream())
    {
        input.CopyTo(memoryStream);
        return memoryStream.ToArray();
    }
}

Note that this doesn't close the input stream.