Skipping every other element after the first

54

I have the general idea of how to do this in Java, but I am learning Python and not sure how to do it.

I need to implement a function that returns a list containing every other element of the list, starting with the first element.

Thus far, I have and not sure how to do from here since I am just learning how for-loops in Python are different:

def altElement(a):
    b = []
    for i in a:
        b.append(a)

    print b

This question is tagged with python for-loop elements

~ Asked on 2012-01-14 22:29:28

The Best Answer is


88

def altElement(a):
    return a[::2]

~ Answered on 2012-01-14 22:34:19


85

Slice notation a[start_index:end_index:step]

return a[::2]

where start_index defaults to 0 and end_index defaults to the len(a).

~ Answered on 2012-01-14 22:33:39


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