I know you can use setdefault(key, value) to set default value for a given key, but is there a way to set default values of all keys to some value after creating a dict ?
Put it another way, I want the dict to return the specified default value for every key I didn't yet set.
This question is related to
python
dictionary
Use defaultdict
from collections import defaultdict
a = {}
a = defaultdict(lambda:0,a)
a["anything"] # => 0
This is very useful for case like this,where default values for every key is set as 0:
results ={ 'pre-access' : {'count': 4, 'pass_count': 2},'no-access' : {'count': 55, 'pass_count': 19}
for k,v in results.iteritems():
a['count'] += v['count']
a['pass_count'] += v['pass_count']
defaultdict
can do something like that for you.
Example:
>>> from collections import defaultdict
>>> d = defaultdict(list)
>>> d
defaultdict(<class 'list'>, {})
>>> d['new'].append(10)
>>> d
defaultdict(<class 'list'>, {'new': [10]})
In case you actually mean what you seem to ask, I'll provide this alternative answer.
You say you want the dict to return a specified value, you do not say you want to set that value at the same time, like defaultdict
does. This will do so:
class DictWithDefault(dict):
def __init__(self, default, **kwargs):
self.default = default
super(DictWithDefault, self).__init__(**kwargs)
def __getitem__(self, key):
if key in self:
return super(DictWithDefault, self).__getitem__(key)
return self.default
Use like this:
d = DictWIthDefault(99, x=5, y=3)
print d["x"] # 5
print d[42] # 99
42 in d # False
d[42] = 3
42 in d # True
Alternatively, you can use a standard dict
like this:
d = {3: 9, 4: 2}
default = 99
print d.get(3, default) # 9
print d.get(42, default) # 99
You can use the following class. Just change zero to any default value you like. The solution was tested in Python 2.7.
class cDefaultDict(dict):
# dictionary that returns zero for missing keys
# keys with zero values are not stored
def __missing__(self,key):
return 0
def __setitem__(self, key, value):
if value==0:
if key in self: # returns zero anyway, so no need to store it
del self[key]
else:
dict.__setitem__(self, key, value)
Is this what you want:
>>> d={'a':1,'b':2,'c':3}
>>> default_val=99
>>> for k in d:
... d[k]=default_val
...
>>> d
{'a': 99, 'b': 99, 'c': 99}
>>>
>>> d={'a':1,'b':2,'c':3}
>>> from collections import defaultdict
>>> d=defaultdict(lambda:99,d)
>>> d
defaultdict(<function <lambda> at 0x03D21630>, {'a': 1, 'c': 3, 'b': 2})
>>> d[3]
99
Not after creating it, no. But you could use a defaultdict
in the first place, which sets default values when you initialize it.
Source: Stackoverflow.com