Convert hexadecimal string hex to a binary string

Question

I found the following way hex to binary conversion   String binAddr   Integer toBinaryString Integer parseInt hexAddr  16       While this approach works for small hex numbers  a hex number such as the following  A14AA1DBDB818F9759   Throws a NumberFormatException    I therefore wrote the following method that seems to work   private String hexToBin String hex       String bin           String binFragment           int iHex      hex   hex trim        hex   hex replaceFirst  0x             for int i   0  i  lt  hex length    i             iHex   Integer parseInt    hex charAt i  16           binFragment   Integer toBinaryString iHex            while binFragment length    lt  4               binFragment    0    binFragment                    bin    binFragment            return bin      The above method basically takes each character in the Hex string and converts it to its binary equivalent pads it with zeros if necessary then joins it to the return value   Is this a proper way of performing a conversion  Or am I overlooking something that may cause my approach to fail   Thanks in advance for any assistance

User · Answer

public static byte   hexToBin String str                int len   str length            byte   out   new byte len   2           int endIndx           for  int i   0  i  lt  len  i   i   2                        endIndx   i   2              if  endIndx  gt  len                  endIndx   len - 1              out i   2     byte  Integer parseInt str substring i  endIndx   16                     return out

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Integer parseInt hex 16       System out print Integer toBinaryString hex      Parse hex String  to integer with base 16 then convert it to Binary String using toBinaryString int  method  example  int num    Integer parseInt  A2B   16    System out print Integer toBinaryString num      Will Print   101000101011   Max Hex vakue Handled by int is FFFFFFF   i e  if FFFFFFF0 is passed ti will give error

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public static byte   hexToBytes String string     int length   string length     byte   data   new byte length   2    for  int i   0  i  lt  length  i    2      data i   2     byte   Character digit string charAt i   16   lt  lt  4    Character digit string charAt i   1   16        return data

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import java util    public class HexadeciamlToBinary      public static void main               Scanner sc new Scanner System in          System out println  enter the hexadecimal number           String s sc nextLine           String p            long n 0         int c 0         for int i s length  -1 i gt  0 i--                     if s charAt i    A                            n n  long  Math pow 16 c  10                c                         else if s charAt i    B                          n n  long  Math pow 16 c  11               c                       else if s charAt i    C                         n n  long  Math pow 16 c  12               c                      else if s charAt i    D                        n n  long  Math pow 16 c  13              c                      else if s charAt i    E                         n n  long  Math pow 16 c  14               c                      else if s charAt i    F                         n n  long  Math pow 16 c  15               c                      else                       n n  long Math pow 16 c   long s charAt i               c                        String s1    k         if n gt 1            while n gt 0                if n 2  0                        k k  0               n n 2                    else                       k k  1               n n 2                      for int i 0 i lt k length   i                  s1 k charAt i  s1            System out println  The respective binary number is     s1             else               System out println  The respective binary number is     n

User · Answer

BigInteger toString radix  will do what you want   Just pass in a radix of 2   static String hexToBin String s      return new BigInteger s  16  toString 2

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Fast  and works for large strings       private String hexToBin String hex           hex   hex replaceAll  0    0000            hex   hex replaceAll  1    0001            hex   hex replaceAll  2    0010            hex   hex replaceAll  3    0011            hex   hex replaceAll  4    0100            hex   hex replaceAll  5    0101            hex   hex replaceAll  6    0110            hex   hex replaceAll  7    0111            hex   hex replaceAll  8    1000            hex   hex replaceAll  9    1001            hex   hex replaceAll  A    1010            hex   hex replaceAll  B    1011            hex   hex replaceAll  C    1100            hex   hex replaceAll  D    1101            hex   hex replaceAll  E    1110            hex   hex replaceAll  F    1111            return hex

User · Answer

With all zeroes   static String hexToBin String s        String preBin   new BigInteger s  16  toString 2       Integer length   preBin length        if  length  lt  8            for  int i   0  i  lt  8 - length  i                  preBin    0    preBin                      return preBin

[java] Convert hexadecimal string (hex) to a binary string

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