How to crop an image using PIL

Question

I want to crop image in the way by removing first 30 rows and last 30 rows from the given image  I have searched but did not get the exact solution  Does somebody have some suggestions

User · Answer

You need to import PIL  Pillow  for this  Suppose you have an image of size 1200  1600  We will crop image from 400  400 to 800  800  from PIL import Image img   Image open  ImageName jpg   area    400  400  800  800  cropped img   img crop area  cropped img show

User · Answer

left  upper  right  lower  means two points      left  upper   right  lower    with an 800x600 pixel image  the image s left upper point is  0  0   the right lower point is  800  600     So  for cutting the image half   from PIL import Image img   Image open  ImageName jpg    img left area    0  0  400  600  img right area    400  0  800  600   img left   img crop img left area  img right   img crop img right area   img left show   img right show       Coordinate System  The Python Imaging Library uses a Cartesian pixel coordinate system  with  0 0  in the upper left corner  Note that the coordinates refer to the implied pixel corners  the centre of a pixel addressed as  0  0  actually lies at  0 5  0 5    Coordinates are usually passed to the library as 2-tuples  x  y   Rectangles are represented as 4-tuples  with the upper left corner given first  For example  a rectangle covering all of an 800x600 pixel image is written as  0  0  800  600

User · Answer

There is a crop   method   w  h   yourImage size yourImage crop  0  30  w  h-30   save

User · Answer

An easier way to do this is using crop from ImageOps  You can feed the number of pixels you want to crop from each side    from PIL import ImageOps  border    0  30  0  30    left  up  right  bottom ImageOps crop img  border

[python] How to crop an image using PIL?

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