[unix] Find files with size in Unix

I am looking for a Unix command to print the files with its size. I used this but it didn't work.

find . -size +10000k -print.

I want to print the size of the file along with the filename/directory.

Assuming you have GNU find:

find . -size +10000k -printf '%s %f\n'

If you want a constant width for the size field, you can do something like:

find . -size +10000k -printf '%10s %f\n'

Note that -size +1000k selects files of at least 10,240,000 bytes (k is 1024, not 1000). You said in a comment that you want files bigger than 1M; if that's 1024*1024 bytes, then this:

find . -size +1M ...

will do the trick -- except that it will also print the size and name of files that are exactly 1024*1024 bytes. If that matters, you could use:

find . -size +1048575c ...

You need to decide just what criterion you want.

Find can be used to print out the file-size in bytes with %s as a printf. %h/%f prints the directory prefix and filename respectively. \n forces a newline.

Example

find . -size +10000k -printf "%h/%f,%s\n"

Output

./DOTT/extract/DOTT/TENTACLE.001,11358470
./DOTT/Day Of The Tentacle.nrg,297308316
./DOTT/foo.iso,297001116