In my python program I am getting this error:
KeyError: 'variablename'
From this code:
path = meta_entry['path'].strip('/'),
Can anyone please explain why this is happening?
This question is related to
python
dictionary
For example, if this is a number :
ouloulou={
1:US,
2:BR,
3:FR
}
ouloulou[1]()
It's work perfectly, but if you use for example :
ouloulou[input("select 1 2 or 3"]()
it's doesn't work, because your input return string '1'. So you need to use int()
ouloulou[int(input("select 1 2 or 3"))]()
Yes, it is most likely caused by non-exsistent key.
In my program, I used setdefault to mute this error, for efficiency concern. depending on how efficient is this line
>>>'a' in mydict.keys()
I am new to Python too. In fact I have just learned it today. So forgive me on the ignorance of efficiency.
In Python 3, you can also use this function,
get(key[, default]) [function doc][1]
It is said that it will never raise a key error.
For dict, just use
if key in dict
and don't use searching in key list
if key in dict.keys()
The latter will be more time-consuming.
This means your array is missing the key you're looking for. I handle this with a function which either returns the value if it exists or it returns a default value instead.
def keyCheck(key, arr, default):
if key in arr.keys():
return arr[key]
else:
return default
myarray = {'key1':1, 'key2':2}
print keyCheck('key1', myarray, '#default')
print keyCheck('key2', myarray, '#default')
print keyCheck('key3', myarray, '#default')
Output:
1
2
#default
I fully agree with the Key error comments. You could also use the dictionary's get() method as well to avoid the exceptions. This could also be used to give a default path rather than None
as shown below.
>>> d = {"a":1, "b":2}
>>> x = d.get("A",None)
>>> print x
None
Let us make it simple if you're using Python 3
mydict = {'a':'apple','b':'boy','c':'cat'}
check = 'c' in mydict
if check:
print('c key is present')
If you need else condition
mydict = {'a':'apple','b':'boy','c':'cat'}
if 'c' in mydict:
print('key present')
else:
print('key not found')
For the dynamic key value, you can also handle through try-exception block
mydict = {'a':'apple','b':'boy','c':'cat'}
try:
print(mydict['c'])
except KeyError:
print('key value not found')mydict = {'a':'apple','b':'boy','c':'cat'}
I received this error when I was parsing dict
with nested for
:
cats = {'Tom': {'color': 'white', 'weight': 8}, 'Klakier': {'color': 'black', 'weight': 10}}
cat_attr = {}
for cat in cats:
for attr in cat:
print(cats[cat][attr])
Traceback:
Traceback (most recent call last):
File "<input>", line 3, in <module>
KeyError: 'K'
Because in second loop should be cats[cat]
instead just cat
(what is just a key)
So:
cats = {'Tom': {'color': 'white', 'weight': 8}, 'Klakier': {'color': 'black', 'weight': 10}}
cat_attr = {}
for cat in cats:
for attr in cats[cat]:
print(cats[cat][attr])
Gives
black
10
white
8
Source: Stackoverflow.com