How to remove all line breaks from a string

Question

I have a text in a textarea and I read it out using the  value attribute   Now I would like to remove all linebreaks  the character that is produced when you press Enter  from my text now using  replace with a regular expression  but how do I indicate a linebreak in a regex   If that is not possible  is there another way

User · Answer

Simple we can remove new line by using text replace   n g   quot   quot    x000D   x000D  const text    Students next year n GO  n For Trip  n   console log  Original      text    var removed new line   text replace   n g        console log  New      removed new line   x000D   x000D   x000D

User · Answer

If you want to remove all control characters  including CR and LF  you can use this   myString replace     x20- x7E  gmi        It will remove all non-printable characters  This are all characters NOT within the ASCII HEX space 0x20-0x7E  Feel free to modify the HEX range as needed

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I am adding my answer  it is just an addon to the above  as for me I tried all the  n options and it didn t work  I saw my text is comming from server with double slash so I used this   var fixedText   yourString replace    r n  n  r   n  gm

User · Answer

Try the following code  It works on all platforms   var break for winDOS    test r nwith r nline r nbreaks   var break for linux    test nwith nline nbreaks   var break for older mac    test rwith rline rbreaks    break for winDOS replace    r  n  r  gm          output  test with line breaks   break for linux replace    r  n  r  gm          output  test with line breaks   break for older mac replace    r  n  r  gm           Output  test with line breaks

User · Answer

How you d find a line break varies between operating system encodings  Windows would be  r n  but Linux just uses  n and Apple uses  r   I found this in JavaScript line breaks   someText   someText replace    r n  n  r  gm         That should remove all kinds of line breaks

User · Answer

A linebreak in regex is  n  so your script would be  var test    this nis na ntest nwith newlines   console log test replace   n g

User · Answer

USE THIS FUNCTION BELOW AND MAKE YOUR LIFE EASY  The easiest approach is using regular expressions to detect and replace newlines in the string  In this case  we use replace function along with string to replace with  which in our case is an empty string   function remove linebreaks  var message         return message replace     r n   gm            In the above expression  g and m are for global and multiline flags

User · Answer

This will replace the line break by empty space  someText   someText replace    r n  n  r  gm  quot  quot     Read more on this article

User · Answer

x000D   x000D  var str      n this is a string  n  n  n  x000D   x000D  console log str   x000D  console log str trim     x000D   x000D   x000D    String trim   removes whitespace from the beginning and end of strings    including newlines   const myString        n  n n Hey   n I m a string             n n   const trimmedString   myString trim     console log trimmedString      outputs   Hey   n I m a string       Here s an example fiddle  http   jsfiddle net BLs8u   NOTE  it only trims the beginning and end of the string  not line breaks or whitespace in the middle of the string

User · Answer

You can use  n in a regex for newlines  and  r for carriage returns   var str2   str replace   n  r g         Different operating systems use different line endings  with varying mixtures of  n and  r  This regex will replace them all

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The simplest solution would be   let str     t n r this   n  t    r  is  r a    n test  t   r  n   str replace   s  g       trim    console log str      logs   this is a test     replace   with   s  g regexp is changing all groups of white-spaces characters to a single space in the whole string then we  trim   the result to remove all exceeding white-spaces before and after the text     Are considered as white-spaces characters     f n r t v  u00a0 u1680  u2000 - u200a u2028 u2029 u202f u205f u3000 ufeff

User · Answer

On mac  just use  n in regexp to match linebreaks  So the code will be string replace   n g       ps  the g followed means match all instead of just the first   On windows  it will be  r n

User · Answer

var str    bar r nbaz nfoo    str replace    r n  g         gt  gt   barbazfoo

User · Answer

If it happens that you don t need this htm characte  amp nbsp shile using str replace    r n  n  r  gm   quot  quot   you can use this str split   n   join      cheers

User · Answer

This is probably a FAQ   Anyhow  line breaks  better  newlines  can be one of Carriage Return  CR   r  on older Macs   Line Feed  LF   n  on Unices incl  Linux  or CR followed by LF   r n  on WinDOS    Contrary to another answer  this has nothing to do with character encoding    Therefore  the most efficient RegExp literal to match all variants is    r  n  r    If you want to match all newlines in a string  use a global match     r  n  r g   respectively   Then proceed with the replace method as suggested in several other answers   Probably you do not want to remove the newlines  but replace them with other whitespace  for example the space character  so that words remain intact

User · Answer

To remove new line chars use this   yourString replace   r  n  g        Then you can trim your string to remove leading and trailing spaces   yourString trim

User · Answer

The answer provided by PointedEars is everything most of us need  But by following  Mathias Bynens s answer  I went on a Wikipedia trip and found this  https   en wikipedia org wiki Newline   The following is a drop-in function that implements everything the above Wiki page considers  new line  at the time of this answer   If something doesn t fit your case  just remove it  Also  if you re looking for performance this might not be it  but for a quick tool that does the job in any case  this should be useful       replaces all  new line  characters contained in  someString  with the given  replacementString  const replaceNewLineChars     someString  replacementString         gt       defaults to just removing   const LF     u 000a       Line Feed   n    const VT     u 000b       Vertical Tab   const FF     u 000c       Form Feed   const CR     u 000d       Carriage Return   r    const CRLF      CR   LF         r n    const NEL     u 0085       Next Line   const LS     u 2028       Line Separator   const PS     u 2029       Paragraph Separator   const lineTerminators    LF  VT  FF  CR  CRLF  NEL  LS  PS      all Unicode  lineTerminators    let finalString   someString normalize  NFD       better safe than sorry  Or is it    for  let lineTerminator of lineTerminators        if  finalString includes lineTerminator        check if the string contains the current  lineTerminator        let regex   new RegExp lineTerminator normalize  NFD     gu       create the  regex  for the current  lineTerminator        finalString   finalString replace regex  replacementString      perform the replacement               return finalString normalize  NFC       return the  finalString   without any Unicode  lineTerminators

[javascript] How to remove all line breaks from a string

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