Print list without brackets in a single row

Question

I have a list in Python e g   names     Sam    Peter    James    Julian    Ann     I want to print the array in a single line without the normal       names     Sam    Peter    James    Julian    Ann   print  names    Will give the output as     Sam    Peter    James    Julian    Ann     That is not the format I want instead I want it to be like this   Sam  Peter  James  Julian  Ann   Note  It must be in a single row

User · Answer

General solution  works on arrays of non-strings    gt  gt  gt  print str names  1 -1   Sam    Peter    James    Julian    Ann

User · Answer

join list  will work only if all the items in the list are strings  If you are looking to convert a list of numbers to a comma separated string  such as a    1  2  3  4  into  1 2 3 4  then you can either  str a  1 -1     1  2  3  4    or  str a  lstrip      rstrip         1  2  3  4    although this won t remove any nested list   To convert it back to a list  a    1 2 3 4  import ast ast literal eval     a        1  2  3  4

User · Answer

print  names     this will work in python 3 if you want them to be printed out as space separated  If you need comma or anything else in between go ahead with  join   solution

User · Answer

This is what you need       join names

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I don t know if this is efficient as others but simple logic always works   import sys name     Sam    Peter    James    Julian    Ann   for i in range 0  len names        sys stdout write names i       if i    len names -1          sys stdout write         Output      Sam  Peter  James  Julian  Ann

User · Answer

Here is a simple one    names     Sam    Peter    James    Julian    Ann   print  names  sep         the star unpacks the list and return every element in the list

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try to use an asterisk before list s name with print statement  names     quot Sam quot    quot Peter quot    quot James quot    quot Julian quot    quot Ann quot     print  names   output  Sam Peter James Julian Ann

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The following function will take in a list and return a string of the lists  items  This can then be used for logging or printing purposes   def listToString inList       outString          if len inList   1          outString   outString str inList 0       if len inList  gt 1          outString   outString str inList 0           for items in inList 1                outString   outString      str items      return outString

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For array of integer type  we need to change it to string type first and than use join function to get clean output without brackets      arr    1  2  3  4  5          print      join map str  arr     OUTPUT - 1  2  3  4  5 For array of string type  we need to use join function directly to get clean output without brackets      arr     quot Ram quot    quot Mohan quot    quot Shyam quot    quot Dilip quot    quot Sohan quot       print      join arr   OUTPUT - Ram  Mohan  Shyam  Dilip  Sohan

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If the input array is Integer type then you need to first convert array into string type array and then use join method for joining with   or space whatever you want  e g    gt  gt  gt  arr    1  2  4  3   gt  gt  gt  print        join arr   Traceback  most recent call last     File   lt stdin gt    line 1  in  lt module gt  TypeError  sequence item 0  expected string  int found  gt  gt  gt  sarr    str a  for a in arr   gt  gt  gt  print        join sarr   1  2  4  3  gt  gt  gt    Direct using of join which will join the integer and string will throw error as show above

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There are two answers   First is use  sep  setting   gt  gt  gt  print  names  sep           The other is below   gt  gt  gt  print      join names

User · Answer

You need to loop through the list and use end    to keep it on one line  names     Sam    Peter    James    Julian    Ann       index 0     for name in names          print names index   end               index    1

User · Answer

print      join names     This  like it sounds  just takes all the elements of the list and joins them with

[python] Print list without brackets in a single row

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