Replace specific characters within strings

Question

I would like to remove specific characters from strings within a vector  similar to the Find and Replace feature in Excel    Here are the data I start with   group  lt - data frame c  12357e    12575e    197e18    e18947     I start with just the first column  I want to produce the second column by removing the e s   group       group no e 12357e      12357 12575e      12575 197e18      19718 e18947      18947

User · Accepted Answer

With a regular expression and the function gsub():

group <- c("12357e", "12575e", "197e18", "e18947")
group
[1] "12357e" "12575e" "197e18" "e18947"

gsub("e", "", group)
[1] "12357" "12575" "19718" "18947"

What gsub does here is to replace each occurrence of "e" with an empty string "".

See ?regexp or gsub for more help.

User · Answer

library stringi               group  lt - c  12357e    12575e    12575e     197e18     e18947                pattern  lt -  e                replacement  lt -                   group  lt - str replace group  pattern  replacement                    group       1   12357    12575    12575     19718   18947

User · Answer

Summarizing 2 ways to replace strings   group lt -data frame group c  12357e    12575e    197e18    e18947      1  Use gsub  group group no e  lt - gsub  e       group group    2  Use the stringr package  group group no e  lt - str replace all group group   e         Both will produce the desire output      group group no e 1 12357e      12357 2 12575e      12575 3 197e18      19718 4 e18947      18947

User · Answer

You do not need to create data frame from vector of strings  if you want to replace some characters in it  Regular expressions is good choice for it as it has been already mentioned by  Andrie and  Dirk Eddelbuettel   Pay attention  if you want to replace special characters  like dots  you should employ full regular expression syntax  as shown in example below   ctr names  lt - c  Czech Republic   New Zealand   Great Britain   gsub             ctr names    this will produce    1   Czech Republic   New Zealand      Great Britain

User · Answer

Regular expressions are your friends   R gt     also adds missing     and sets column name R gt  group lt -data frame group c  12357e    12575e    197e18    e18947       R gt  group    group 1 12357e 2 12575e 3 197e18 4 e18947   Now use gsub   with the simplest possible replacement pattern  empty string   R gt  group groupNoE  lt - gsub  e       group group  R gt  group    group groupNoE 1 12357e    12357 2 12575e    12575 3 197e18    19718 4 e18947    18947 R gt

User · Answer

Use the stringi package   require stringi   group lt -data frame c  12357e    12575e    197e18    e18947    stri replace all group  1       fixed  e    1   12357   12575   19718   18947

[r] Replace specific characters within strings

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