Here i am trying to wrap my head around promises.Here on first request i fetch a set of links.and on next request i fetch the content of first link.But i want to make a delay before returning next promise object.So i use setTimeout on it.But it gives me the following JSON error (without setTimeout() it works just fine
)
SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data
i would like to know why it fails?
let globalObj={};
function getLinks(url){
return new Promise(function(resolve,reject){
let http = new XMLHttpRequest();
http.onreadystatechange = function(){
if(http.readyState == 4){
if(http.status == 200){
resolve(http.response);
}else{
reject(new Error());
}
}
}
http.open("GET",url,true);
http.send();
});
}
getLinks('links.txt').then(function(links){
let all_links = (JSON.parse(links));
globalObj=all_links;
return getLinks(globalObj["one"]+".txt");
}).then(function(topic){
writeToBody(topic);
setTimeout(function(){
return getLinks(globalObj["two"]+".txt"); // without setTimeout it works fine
},1000);
});
This question is related to
javascript
json
promise
To keep the promise chain going, you can't use setTimeout()
the way you did because you aren't returning a promise from the .then()
handler - you're returning it from the setTimeout()
callback which does you no good.
Instead, you can make a simple little delay function like this:
function delay(t, v) {
return new Promise(function(resolve) {
setTimeout(resolve.bind(null, v), t)
});
}
And, then use it like this:
getLinks('links.txt').then(function(links){
let all_links = (JSON.parse(links));
globalObj=all_links;
return getLinks(globalObj["one"]+".txt");
}).then(function(topic){
writeToBody(topic);
// return a promise here that will be chained to prior promise
return delay(1000).then(function() {
return getLinks(globalObj["two"]+".txt");
});
});
Here you're returning a promise from the .then()
handler and thus it is chained appropriately.
You can also add a delay method to the Promise object and then directly use a .delay(x)
method on your promises like this:
function delay(t, v) {_x000D_
return new Promise(function(resolve) { _x000D_
setTimeout(resolve.bind(null, v), t)_x000D_
});_x000D_
}_x000D_
_x000D_
Promise.prototype.delay = function(t) {_x000D_
return this.then(function(v) {_x000D_
return delay(t, v);_x000D_
});_x000D_
}_x000D_
_x000D_
_x000D_
Promise.resolve("hello").delay(500).then(function(v) {_x000D_
console.log(v);_x000D_
});
_x000D_
Or, use the Bluebird promise library which already has the .delay()
method built-in.
.then(() => new Promise((resolve) => setTimeout(resolve, 15000)))
UPDATE:
when I need sleep in async function I throw in
await new Promise(resolve => setTimeout(resolve, 1000))
In node.js you can also do the following:
const { promisify } = require('util')
const delay = promisify(setTimeout)
delay(1000).then(() => console.log('hello'))
The shorter ES6 version of the answer:
const delay = t => new Promise(resolve => setTimeout(resolve, t));
And then you can do:
delay(3000).then(() => console.log('Hello'));
If you are inside a .then() block and you want to execute a settimeout()
.then(() => {
console.log('wait for 10 seconds . . . . ');
return new Promise(function(resolve, reject) {
setTimeout(() => {
console.log('10 seconds Timer expired!!!');
resolve();
}, 10000)
});
})
.then(() => {
console.log('promise resolved!!!');
})
output will as shown below
wait for 10 seconds . . . .
10 seconds Timer expired!!!
promise resolved!!!
Happy Coding!
Source: Stackoverflow.com