How to get selected path and name of the file opened with file dialog

Question

I need the path name and file name of the file that is opened with File Dialog  I want to show this information with a hyperlink in my worksheet   With this code I have the file path   Sub GetFilePath    Set myFile   Application FileDialog msoFileDialogOpen  With myFile      Title    Choose File       AllowMultiSelect   False     If  Show  lt  gt  -1 Then         Exit Sub     End If FileSelected    SelectedItems 1  End With  ActiveSheet Range  A1     FileSelected End Sub   I m still looking for a way to get the filename

User · Accepted Answer

Try this  Sub Demo       Dim lngCount As Long     Dim cl As Range      Set cl   ActiveCell       Open the file dialog     With Application FileDialog msoFileDialogOpen           AllowMultiSelect   True          Show           Display paths of each file selected         For lngCount   1 To  SelectedItems Count               Add Hyperlinks             cl Worksheet Hyperlinks Add                   Anchor  cl  Address   SelectedItems lngCount                     TextToDisplay   SelectedItems lngCount                Add file name              cl Offset 0  1                       Mid  SelectedItems lngCount   InStrRev  SelectedItems lngCount          1                Add file as formula             cl Offset 0  1  FormulaR1C1                        TRIM RIGHT SUBSTITUTE RC -1        REPT       99   99                  Set cl   cl Offset 1  0          Next lngCount     End With End Sub

User · Answer

The code starts file search from root colon  If I want to start search from a specific directory  to avoid going to that directory every time  where I should put one  I did it like  Sub GetFilePath   FileSelected    G  Audits A2010  Set myFile   Application FileDialog msoFileDialogOpen  With myFile  Title    Choose File   AllowMultiSelect   False If  Show  lt  gt  -1 Then Exit Sub End If FileSelected    SelectedItems 1  End With  ActiveSheet Range  C14     FileSelected End Sub   But it could not start reach from  G  Audits A2010

User · Answer

FileNameOnly   Dir  SelectedItems 1

User · Answer

You can get any part of the file path using the FileSystemObject  GetFileName filepath  gives you what you want   Modified code below   Sub GetFilePath   Dim objFSO as New FileSystemObject  Set myFile   Application FileDialog msoFileDialogOpen  With myFile  Title    Choose File   AllowMultiSelect   False If  Show  lt  gt  -1 Then Exit Sub End If FileSelected    SelectedItems 1  End With  ActiveSheet Range  A1     FileSelected  The file path ActiveSheet Range  A2     objFSO GetFileName FileSelected   The file name End Sub

User · Answer

I think this is the simplest way to get to what you want    Credit to JMK s answer for the first part  and the hyperlink part was adapted from http   msdn microsoft com en-us library office ff822490 v office 15  aspx   Gets the entire path to the file including the filename using the open file dialog Dim filename As String filename   Application GetOpenFilename   Adds a hyperlink to cell b5 in the currently active sheet With ActiveSheet   Hyperlinks Add Anchor   Range  b5       Address  filename     ScreenTip   The screenTIP      TextToDisplay  filename End With

User · Answer

To extract only the filename from the path  you can do the following   varFileName   Mid fDialog SelectedItems 1   InStrRev fDialog SelectedItems 1          1  Len fDialog SelectedItems 1

User · Answer

I think this will do   Dim filename As String filename   Application GetOpenFilename

User · Answer

The below command is enough to get the path of the file from a dialog box -   my FileName   Application GetOpenFilename  Excel Files    tsv     txt

User · Answer

Sub GetFilePath    Set myFile   Application FileDialog msoFileDialogOpen   With myFile   Title    Choose File    AllowMultiSelect   False  If  Show  lt  gt  -1 Then  Exit Sub  End If  FileSelected   Replace  SelectedItems 1    InitialFileName       End With  ActiveSheet Range  A1     FileSelected  End Sub

User · Answer

After searching different websites looking for a solution as to how to separate the full path from the file name once the full one-piece information has been obtained from the Open File Dialog  and seeing how  complex  the solutions given were for an Excel newcomer like me  I wondered if there could be a simpler solution  So I started to work on it on my own and I came to this possibility   I have no idea if somebody got the same idea before  Being so simple  if somebody has  I excuse myself     Dim fPath As String Dim fName As String Dim fdString As String  fdString    the OpenFileDialog FileName    Get just the path by finding the last     in the string from the end of it  fPath   Left fdString  InStrRev fdString          Get just the file name by finding the last     in the string from the end of it  fName   Mid fdString  InStrRev fdString         1    Just to check the result  Msgbox  File path     amp  vbLF  amp  fPath  amp  vbLF  amp  vblF  amp   File name     amp  vbLF  amp  fName    AND THAT S IT     Just give it a try  and let me know how it goes

User · Answer

From office 2010  we won t be able to use the common dialog box control  so it s nice to use the Application object to get the desired results   Here I got a text box and Command button - paste the following code under the command button click event  which will open the file dialog box and add the File name to the Text box   Dim sFileName  As String  sFileName   Application GetOpenFilename  MS Excel    xlsx     xls    TextBox1 Text   sFileName

User · Answer

I think you want this   Dim filename As String filename   Application GetOpenFilename  Dim cell As Range cell   Application Range  A1   cell Value   filename

[excel] How to get selected path and name of the file opened with file dialog?

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