I am getting this error in this PHP code on line 3, what could be wrong? This code has been taken from php manual user notes by frank at interactinet dot com
<?php
public function myMethod()
{
return 'test';
}
public function myOtherMethod()
{
return null;
}
if($val = $this->myMethod())
{
// $val might be 1 instead of the expected 'test'
}
if( ($val = $this->myMethod()) )
{
// now $val should be 'test'
}
// or to check for false
if( !($val = $this->myMethod()) )
{
// this will not run since $val = 'test' and equates to true
}
// this is an easy way to assign default value only if a value is not returned:
if( !($val = $this->myOtherMethod()) )
{
$val = 'default'
}
?>
This question is related to
php
The public
keyword is used only when declaring a class method.
Since you're declaring a simple function and not a class you need to remove public
from your code.
You can remove public keyword from your functions, because, you have to define a class in order to declare public, private or protected function
Source: Stackoverflow.com