[c] How to convert int to float in C?

I am trying to solve:

int total=0, number=0;
float percentage=0.0;

percentage=(number/total)*100;
printf("%.2f", percentage);

If the value of the number is 50 and the total is 100, I should get 50.00 as percentage and that is what I want. But I keep getting 0.00 as the answer and tried many changes to the types but they didn't work.

This Should work Making it Round to 2 Point

       int a=53214
       parseFloat(Math.round(a* 100) / 100).toFixed(2);

This can give you the correct Answer

#include <stdio.h>
int main()
{
    float total=100, number=50;
    float percentage;
    percentage=(number/total)*100;
    printf("%0.2f",percentage);
    return 0;
}

This should give you the result you want.

double total = 0;
int number = 0;
float percentage = number / total * 100
printf("%.2f",percentage);

Note that the first operand is a double

I routinely multiply by 1.0 if I want floating point, it's easier than remembering the rules.

Change your code to:

int total=0, number=0;
float percentage=0.0f;

percentage=((float)number/total)*100f;
printf("%.2f", (double)percentage);

integer division in C truncates the result so 50/100 will give you 0

If you want to get the desired result try this :

((float)number/total)*100

or

50.0/100

You are doing integer arithmetic, so there the result is correct. Try

percentage=((double)number/total)*100;

BTW the %f expects a double not a float. By pure luck that is converted here, so it works out well. But generally you'd mostly use double as floating point type in C nowadays.

No, because you do the expression using integers, so you divide the integer 50 by the integer 100, which results in the integer 0. Type cast one of them to a float and it should work.