PHP Warning include once Failed opening for inclusion include path C xampp php PEAR

Question

I know this error is very common  I ve tried to search google  I did the tricks to no avail   So my setup is  I have 3 directories    CLASSES- constants  PAGES  INITCONTROLS   EDIT   I ve got new error    Warning  require once initcontrols config php   function require-once   failed to open stream  No such file or directory in   below is my fragment of code    require once  initcontrols config php      lt div gt   lt  php   file    initcontrols header myworks php    include once  file    echo  plHeader   gt      lt  div gt    What is still lacking in here  Thanks for all help in advance

User · Answer

The include path is set against the server configuration (PHP.ini) but the include path you specify is relative to that path so in your case the include path is (actual path in windows):

C:\xampp\php\PEAR\initcontrols\header_myworks.php

providing the path you pasted in the subject is correct. Make sure your file is located there.

For more info you can get and set the include path programmatically.

User · Answer

This should work if current file is located in same directory where initcontrols is    lt  php  ds   DIRECTORY SEPARATOR   base dir   realpath dirname   FILE        ds            ds  require once    base dir initcontrols  ds config php      gt   lt div gt   lt  php   file      base dir initcontrols  ds header myworks php    include once  file    echo  plHeader   gt      lt  div gt

User · Answer

Put in config php this   config  rewrite short tags     FALSE

User · Answer

It is because you use a relative path   The easy way to fix this is by using the   DIR   magic constant  like   require once   DIR     initcontrols config php      From the PHP doc      The directory of the file  If used inside an include  the directory of   the included file is returned

[php] PHP Warning: include_once() Failed opening '' for inclusion (include_path='.;C:\xampp\php\PEAR')

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