How to repeat a char using printf

Question

I d like to do something like printf      count  char  to repeat a character count times   What is the right format-string to accomplish this   EDIT  Yes  it is obvious that I could call printf   in a loop  but that is just what I wanted to avoid

User · Answer

you can make a function that do this job and use it

#include <stdio.h>

void repeat (char input , int count )
{
    for (int i=0; i != count; i++ )
    {
        printf("%c", input);
    }
}

int main()
{
    repeat ('#', 5);
    return 0;
}

This will output

#####

User · Answer

There is no such thing  You ll have to either write a loop using printf or puts  or write a function that copies the string count times into a new string

User · Answer

include  lt stdio h gt   include  lt string h gt   void repeat char unsigned int cnt  char ch        char buffer cnt   1         assuming you want to repeat the c character 30 times       memset buffer ch cnd   buffer cnt    0       printf   s  buffer

User · Answer

If you have a compiler that supports the alloca   function  then this is possible solution  quite ugly though    printf   s    char  memset memset alloca 10     0   10    x   9      It basically allocates 10 bytes on the stack which are filled with   0  and then the first 9 bytes are filled with  x    If you have a C99 compiler  then this might be a neater solution   for  int i   0   i  lt  10   i    printf   c    x

User · Answer

Short answer - yes  long answer  not how you want it   You can use the    form of printf  which accepts a variable width  And  if you use  0  as your value to print  combined with the right-aligned text that s zero padded on the left    printf   0 d n   20  0     produces    00000000000000000000   With my tongue firmly planted in my cheek  I offer up this little horror-show snippet of code    Some times you just gotta do things badly to remember why you try so hard the rest of the time    include  lt stdio h gt   int width   20  char buf 4096    void subst char  s  char from  char to        while   s    from       s     to     int main         sprintf buf    0 d   width  0       subst buf   0    -        printf   s n   buf       return 0

User · Answer

i think doing some like this   void printchar char c  int n        int i       for i 0 i lt n i             print   c  c      printchar     10

User · Answer

If you limit yourself to repeating either a 0 or a space you can do   For spaces   printf    s   count         For zeros   printf   0 d   count  0

User · Answer

char buffer 41    memset buffer   -   40         initialize all with the  -  character lt br   gt  lt br   gt  buffer 40    0                 put a NULL at the end lt br   gt   printf   s n   buffer          show 40 dashes lt br   gt

User · Answer

printf     s n  n  char    memset buffer c n      n  lt   sizeof buffer    maybe also n  lt  2 16   However the optimizer may change it to puts buffer  and then the lack of EoS will        And the assumption is that memset is an assembler instruction  but still a loop be it on  chip    Strictly seen there is no solution given you precondition  No loop

User · Answer

You can use the following technique   printf     s   5                          This will print          It works for me on Visual Studio  no reason it shouldn t work on all C compilers

User · Answer

printf doesn t do that -- and printf is overkill for printing a single character   char c        int count   42  for  i   0  i  lt  count  i           putchar c       Don t worry about this being inefficient  putchar   buffers its output  so it won t perform a physical output operation for each character unless it needs to

User · Answer

In c   you could use std  string to get repeated character  printf   s  std  string count char  c str       For example   printf   s  std  string 5  a   c str       output   aaaaa

[c] How to repeat a char using printf?

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