mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]
I need the index position of all items that contain 'aa'. I'm having trouble combining enumerate() with partial string matching. I'm not even sure if I should be using enumerate.
I just need to return the index positions: 0,2,5
spell_list = ["Tuesday", "Wednesday", "February", "November", "Annual", "Calendar", "Solstice"]
index=spell_list.index("Annual")
print(index)
Without enumerate()
:
>>> mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]
>>> l = [mylist.index(i) for i in mylist if 'aa' in i]
>>> l
[0, 2, 5]
Your idea to use enumerate()
was correct.
indices = []
for i, elem in enumerate(mylist):
if 'aa' in elem:
indices.append(i)
Alternatively, as a list comprehension:
indices = [i for i, elem in enumerate(mylist) if 'aa' in elem]
Source: Stackoverflow.com