How to index characters in a Golang string

Question

How to get an  E  output rather than 69   package main  import  fmt   func main         fmt Print  HELLO  1       Does Golang have function to convert a char to byte and vice versa

User · Answer

Another Solution to isolate a character in a string

package main
import "fmt"

   func main() {
        var word string = "ZbjTS"

       // P R I N T 
       fmt.Println(word)
       yo := string([]rune(word)[0])
       fmt.Println(yo)

       //I N D E X 
       x :=0
       for x < len(word){
           yo := string([]rune(word)[x])
           fmt.Println(yo)
           x+=1
       }

}

for string arrays also:

fmt.Println(string([]rune(sArray[0])[0]))

// = commented line

User · Answer

Try this to get the charecters by their index   package main  import          fmt         strings     func main        str    strings Split  HELLO          fmt Print str 1

User · Answer

String characters are runes  so to print them  you have to turn them back into String  fmt Print string  quot HELLO quot  1

User · Answer

How about this   fmt Printf   c   HELLO  1     As Peter points out  to allow for more than just ASCII   fmt Printf   c     rune  HELLO   1

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Interpreted string literals are character sequences between double quotes    using the  possibly multi-byte  UTF-8 encoding of individual characters  In UTF-8  ASCII characters are single-byte corresponding to the first 128 Unicode characters  Strings behave like slices of bytes  A rune is an integer value identifying a Unicode code point  Therefore   package main  import  fmt   func main         fmt Println string  Hello  1                    ASCII only     fmt Println string   rune  Hello       1       UTF-8     fmt Println string   rune  Hello       8       UTF-8     Output   e e       Read   Go Programming Language Specification section on Conversions   The Go Blog  Strings  bytes  runes and characters in Go

User · Answer

Can be done via slicing too package main  import  quot fmt quot   func main         fmt Print  quot HELLO quot  1 2      NOTE  This solution only works for ASCII characters

User · Answer

Go doesn t really have a character type as such  byte is often used for ASCII characters  and rune is used for Unicode characters  but they are both just aliases for integer types  uint8 and int32   So if you want to force them to be printed as characters instead of numbers  you need to use Printf   c   x   The  c format specification works for any integer type

User · Answer

The general solution to interpreting a char as a string is string  HELLO  1     Rich s solution also works  of course

User · Answer

You can also try typecasting it with string   package main  import  fmt   func main         fmt Println string  Hello  1

[string] How to index characters in a Golang string?

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