Convert date to day name e g Mon Tue Wed

Question

I have a variable that outputs the date in the following format   201308131830   Which is 2013 - Aug - 13 - 18 30  I am using this to retrieve the day name but it is getting the wrong days    dayname   date  D   strtotime  longdate      Any idea what I am doing wrong

User · Answer

Seems like you could use date   and the lowercase  L  format character in the following way    weekday name   date  l    timestamp     Works well for me  here is the doc  http   php net manual en function date php

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echo date  D   strtotime  date    echo date  l   strtotime  date      Result  Tue Tuesday

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For other language use day of week to recognize day name  For example for Persian use below code   dayName   getDayName date  w   strtotime  2019-11-14           function getDayName  dayOfWeek             switch   dayOfWeek               case 6                  return                     case 0                  return                        case 1                  return                        case 2                  return                        case 3                  return                          case 4                  return                         case 5                  return                     default                  return                        More info   https   www php net manual en function date php

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Your code works for me   date    15-12-2016    nameOfDay   date  D   strtotime  date    echo  nameOfDay    Use l instead of D  if you prefer the full textual representation of the name

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You can not use strtotime as your time format is not within the supported date and time formats of PHP   Therefor  you have to create a valid date format first making use of createFromFormat function     creating a valid date format  newDate   DateTime  createFromFormat  YmdHi    longdate      formating the date as we want  finalDate    newDate- gt format  D

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This is what happens when you store your dates and times in a non-standard format  Working with them become problematic    datetime   DateTime  createFromFormat  YmdHi    201308131830    echo  datetime- gt format  D      See it in action

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date   new  DateTime  quot now quot   new  DateTimeZone  Asia Calcutta                day    date- gt format  D              weekendnaame   weekedName              weekid   weekendnaame  day              dayname   0           weekiarray   weekendArray  weekid           foreach   weekiarray as  key   gt   value                if  in array  value   request- gt get  week id                              dayname    key 1              break                          weeknDate  dayname    function weeked       week   array  quot 1 quot   gt  quot Sunday quot    quot 2 quot   gt  quot Monday quot    quot 3 quot   gt  quot Tuesday quot    quot 4 quot   gt  quot Wednesday quot    quot 5 quot   gt  quot Thursday quot    quot 6 quot   gt  quot Friday quot    quot 7 quot   gt  quot Saturday quot      return  week    function weekendArray  day            favcolor    day   switch   favcolor      case 1       array   array 2 3 4 5 6 7 1       break    case 2       array   array 3 4 5 6 7 1 2       break    case 3       array   array 4 5 6 7 1 2 3       break      case 4       array   array 5 6 7 1 2 3 4       break      case 5       array   array 6 7 1 2 3 4 5       break      case 6       array   array 7 1 2 3 4 5 6       break       case 7       array   array 1 2 3 4 5 6 7       break    default       array   array 1 2 3 4 5 6 7     return   array    function weekedName       week   array  quot Sun quot   gt 0  quot Mun quot   gt 1  quot Tue quot   gt 3  quot Wed quot   gt 4  quot Thu quot   gt 5  quot Fri quot   gt 6  quot Sat quot   gt 7     return  week

User · Answer

Very Simply Short week day name with Month and year echo date  D  d-M-y     output Tue  16-Feb-21  as per my requirements return  item- gt start time- gt format  quot D  d-M quot     output Tue  16-Feb

User · Answer

Your code works for me    input   201308131830   echo date  Y-M-d H i s  strtotime  input       n   echo date  D   strtotime  input       n     Output   2013-Aug-13 18 30 00 Tue   However if you pass 201308131830 as a number it is 50 to 100x larger than can be represented by a 32-bit integer   dependent on your system s specific implementation  If your server PHP version does not support 64-bit integers then the number will overflow and probably end up being output as a negative number and date   will default to Jan 1  1970 00 00 00 GMT   Make sure whatever source you are retrieving this data from returns that date as a string  and keep it as a string

[php] Convert date to day name e.g. Mon, Tue, Wed

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