Convert string without any separator to list

Question

I have a phone number string   e g    123-456-7890   that I want to turn into a list that looks like      1  2  3  -        0     Why  So I can go iterate through the list and remove all the symbols  so I m left with a list of only digits  which I can then convert back to a string   What s the best way to solve this problem  None of the solutions I ve come across are applicable  because I don t have any special characters in-between the digits  so I can t split the string there    Any ideas  I really appreciate it   Edit - this is what I ve tried   x   row translate None  string digits  list   x split     Also    filter lambda x  x isdigit

User · Answer

You can use the re module   import re re sub r  D         123-456-7890     This will replace all non-digits with

User · Answer

You can use str translate  you just have to give it the right arguments    gt  gt  gt  dels    join chr x  for x in range 256  if not chr x  isdigit     gt  gt  gt    1-617-555-1212  translate None  dels   16175551212    N b   This won t work with unicode strings in Python2  or at all in Python3  For those environments  you can create a custom class to pass to unicode translate    gt  gt  gt  class C         def   getitem   self  i             if unichr i  isdigit                 return i       gt  gt  gt  u  1-617 555 1212  translate C    u 16175551212    This works with non-ASCII digits  too    gt  gt  gt  print u   u00b9- uff1617 555 1212  translate C    encode  utf-8     6175551212

User · Answer

join filter str isdigit    123-456-7890

User · Answer

Instead of converting to a list  you could just iterate over the first string and create a second string by adding each of the digit characters you find to that new string

User · Answer

Did you try list x      y     123-456-7890   c  list y   c          1    2    3    -    4    5    6    -    7    8    9    0

User · Answer

I know this question has been answered  but just to point out what timeit has to say about the solutions efficiency  Using these parameters   size   30 s    str random randint 0  9   for i in range size      size 3      -   random shuffle s  s      join         s  timec   1000   That is the  phone number  has 30 digits  1 plus sing and 10  -   I ve tested these approaches   def justdigits s       justdigitsres          for char in s          if char isdigit                justdigitsres    str char      return justdigitsres  re compiled   re compile r  D    print  Filter   ss    timeit Timer lambda      join filter str isdigit  s    timeit timec   print  GE   ss    timeit Timer lambda      join n for n in s if n isdigit     timeit timec   print  LC   ss    timeit Timer lambda      join  n for n in s if n isdigit      timeit timec   print  For loop   ss    timeit Timer lambda   justdigits s   timeit timec   print  RE   ss    timeit Timer lambda   re sub r  D       s   timeit timec   print  REC   ss    timeit Timer lambda   re compiled sub     s   timeit timec   print  Translate   ss    timeit Timer lambda   s translate None    -    timeit timec     And came out with these results   Filter  0 0145790576935s GE  0 0185861587524s LC  0 0151798725128s For loop  0 0242128372192s RE  0 0120108127594s REC  0 00868797302246s Translate  0 00118899345398s   Apparently GEs and LCs are still slower than a regex or a compiled regex  And apparently my CPython 2 6 6 didn t optimize the string addition that much  translate appears to be the fastest  which is expected as the problem is stated as  ignore these two symbols   rather than  get these numbers  and I believe is quite low-level    And for size   100   Filter  0 0357120037079s GE  0 0465779304504s LC  0 0428011417389s For loop  0 0733139514923s RE  0 0213229656219s REC  0 0103371143341s Translate  0 000978946685791s   And for size   1000   Filter  0 212141036987s GE  0 198996067047s LC  0 196880102158s For loop  0 365696907043s RE  0 0880808830261s REC  0 086804151535s Translate  0 00587010383606s

User · Answer

You mean that you want something like      join n for n in phone str if n isdigit      This uses the fact that strings are iterable   They yield 1 character at a time when you iterate over them     Regarding your efforts   This one actually removes all of the digits from the string leaving you with only non-digits   x   row translate None  string digits    This one splits the string on runs of whitespace  not after each character   list   x split

User · Answer

Make a list your string     gt  gt  gt  s    mep   gt  gt  gt  list s    m    e    p

User · Answer

A python string is a list of characters   You can iterate over it right now   justdigits      for char in string      if char isdigit            justdigits    str char

[python] Convert string (without any separator) to list

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