I know this is simple, and I need to search in Google. I tried my best and I could not find a better solution. I have a form field, which takes some input and a select field, which has some values. It also has "Other" value.
What I want is:
If the user selects the 'Other' option, a text field to specify that 'Other' should be displayed. When a user selects another option (than 'Other') I want to hide it again. How can I perform that using JQuery?
This is my JSP code
<label for="db">Choose type</label>
<select name="dbType" id=dbType">
<option>Choose Database Type</option>
<option value="oracle">Oracle</option>
<option value="mssql">MS SQL</option>
<option value="mysql">MySQL</option>
<option value="other">Other</option>
</select>
<div id="otherType" style="display:none;">
<label for="specify">Specify</label>
<input type="text" name="specify" placeholder="Specify Databse Type"/>
</div>
Now I want to show the DIV tag**(id="otherType")** only when the user selects Other. I want to try JQuery. This is the code I tried
<script type="text/javascript"
src="jquery-ui-1.10.0/tests/jquery-1.9.0.js"></script>
<script src="jquery-ui-1.10.0/ui/jquery-ui.js"></script>
<script>
$('#dbType').change(function(){
selection = $('this').value();
switch(selection)
{
case 'other':
$('#otherType').show();
break;
case 'default':
$('#otherType').hide();
break;
}
});
</script>
But I am not able to get this. What should I do? Thanks
This question is related to
javascript
jquery
html
jsp
$('#dbType').change(function(){
var selection = $(this).val();
if(selection == 'other')
{
$('#otherType').show();
}
else
{
$('#otherType').hide();
}
});
You have to use val() instead of value() and you have missed starting quote id=dbType" should be id="dbType"
Change
selection = $('this').value();
To
selection = $(this).val();
or
selection = this.value;
I got its answer. Here is my code
<label for="db">Choose type</label>
<select name="dbType" id=dbType">
<option>Choose Database Type</option>
<option value="oracle">Oracle</option>
<option value="mssql">MS SQL</option>
<option value="mysql">MySQL</option>
<option value="other">Other</option>
</select>
<div id="other" class="selectDBType" style="display:none;">
<label for="specify">Specify</label>
<input type="text" name="specify" placeholder="Specify Databse Type"/>
</div>
And my script is
$(function() {
$('#dbType').change(function() {
$('.selectDBType').slideUp("slow");
$('#' + $(this).val()).slideDown("slow");
});
});
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
function myfun(){
$(document).ready(function(){
$("#select").click(
function(){
var data=$("#select").val();
$("#disp").val(data);
});
});
}
</script>
</head>
<body>
<p>id <input type="text" name="user" id="disp"></p>
<select id="select" onclick="myfun()">
<option name="1"value="1">first</option>
<option name="2"value="2">second</option>
</select>
</body>
</html>
$(document).ready(function () {
toggleFields(); // call this first so we start out with the correct visibility depending on the selected form values
// this will call our toggleFields function every time the selection value of our other field changes
$("#dbType").change(function () {
toggleFields();
});
});
// this toggles the visibility of other server
function toggleFields() {
if ($("#dbType").val() === "other")
$("#otherServer").show();
else
$("#otherServer").hide();
}
HTML:
<p>Choose type</p>
<p>Server:
<select id="dbType" name="dbType">
<option>Choose Database Type</option>
<option value="oracle">Oracle</option>
<option value="mssql">MS SQL</option>
<option value="mysql">MySQL</option>
<option value="other">Other</option>
</select>
</p>
<div id="otherServer">
<p>Server:
<input type="text" name="server_name" />
</p>
<p>Port:
<input type="text" name="port_no" />
</p>
</div>
<p align="center">
<input type="submit" value="Submit!" />
</p>
Source: Stackoverflow.com