[batch-file] Batch Extract path and filename from a variable

How can I extract path and filename from a variable?

Setlocal EnableDelayedExpansion
set file=C:\Users\l72rugschiri\Desktop\fs.cfg

I want to do that without using any function or any GOTO. is it possible?

You can only extract path and filename from (1) a parameter of the BAT itself %1, or (2) the parameter of a CALL %1 or (3) a local FOR variable %%a.

in HELP CALL or HELP FOR you may find more detailed information:

%~1 - expands %1 removing any surrounding quotes (")
%~f1 - expands %1 to a fully qualified path name
%~d1 - expands %1 to a drive letter only
%~p1 - expands %1 to a path only
%~n1 - expands %1 to a file name only
%~x1 - expands %1 to a file extension only
%~s1 - expanded path contains short names only
%~a1 - expands %1 to file attributes
%~t1 - expands %1 to date/time of file
%~z1 - expands %1 to size of file

And then try the following:

Either pass the string to be parsed as a parameter to a CALL

call :setfile ..\Desktop\fs.cfg
echo %file% = %filepath% + %filename%
goto :eof

:setfile
set file=%~f1
set filepath=%~dp1
set filename=%~nx1
goto :eof

or the equivalent, pass the filename as a local FOR variable

for %%a in (..\Desktop\fs.cfg) do (
    set file=%%~fa
    set filepath=%%~dpa
    set filename=%%~nxa
)    
echo %file% = %filepath% + %filename%

All of this works for me:

@Echo Off
Echo Directory = %~dp0
Echo Object Name With Quotations=%0
Echo Object Name Without Quotes=%~0
Echo Bat File Drive = %~d0
Echo Full File Name = %~n0%~x0
Echo File Name Without Extension = %~n0
Echo File Extension = %~x0
Pause>Nul

Output:

Directory = D:\Users\Thejordster135\Desktop\Code\BAT\

Object Name With Quotations="D:\Users\Thejordster135\Desktop\Code\BAT\Path_V2.bat"

Object Name Without Quotes=D:\Users\Thejordster135\Desktop\Code\BAT\Path_V2.bat

Bat File Drive = D:

Full File Name = Path.bat

File Name Without Extension = Path

File Extension = .bat

Late answer, I know, but for me the following script is quite useful - and it answers the question too, hitting two flys with one flag ;-)

The following script expands SendTo in the file explorer's context menu:

@echo off
cls
if "%~dp1"=="" goto Install

REM change drive, then cd to path given and run shell there
%~d1
cd "%~dp1"
cmd /k
goto End

:Install
rem No arguments: Copies itself into SendTo folder
copy "%0" "%appdata%\Microsoft\Windows\SendTo\A - Open in CMD shell.cmd"

:End

If you run this script without any parameters by double-clicking on it, it will copy itself to the SendTo folder and renaming it to "A - Open in CMD shell.cmd". Afterwards it is available in the "SentTo" context menu.

Then, right-click on any file or folder in Windows explorer and select "SendTo > A - Open in CMD shell.cmd"

The script will change drive and path to the path containing the file or folder you have selected and open a command shell with that path - useful for Visual Studio Code, because then you can just type "code ." to run it in the context of your project.

How does it work?

%0 - full path of the batch script
%~d1 - the drive contained in the first argument (e.g. "C:")
%~dp1 - the path contained in the first argument
cmd /k - opens a command shell which stays open

Not used here, but %~n1 is the file name of the first argument.

I hope this is helpful for someone.

if you want infos from the actual running batchfile, try this :

@echo off
set myNameFull=%0
echo myNameFull     %myNameFull%
set myNameShort=%~n0
echo myNameShort    %myNameShort%
set myNameLong=%~nx0
echo myNameLong     %myNameLong%
set myPath=%~dp0
echo myPath         %myPath%
set myLogfileWpath=%myPath%%myNameShort%.log
echo myLogfileWpath %myLogfileWpath%

more samples? C:> HELP CALL

%0 = parameter 0 = batchfile %1 = parameter 1 - 1st par. passed to batchfile... so you can try that stuff (e.g. "~dp") between 1st (e.g. "%") and last (e.g. "1") also for parameters