[php] Popup window in PHP?

here's a quick question:

How do you make a window pop up for your error handling in php? Is javascript the only way to do this or is there a way to do this in PHP?

i have a PHP-file, and one of the lines of code is the following:

 echo implode('<br />', $errors);

This line of code catches all the errors coming from my form, as following:

 if (strlen($_POST['name'])<3) $errors[] = 'De naam van uw bedrijf moet minstens 3 letters bevatten';
  if (strlen($_POST['number'])<9) $errors[] = 'Uw nummer moet minstens 9 nummers bevatten';
  if (!preg_match($regexp_mail, $_POST['email'])) $errors[] = 'Onjuist E-mailadres';

when somebody presses submit on my form, the errors will show themselves on a separate page, i want this in a pop-up window. Thank you in advance

if (isset($_POST['Register']))
    {
        $ErrorArrays = array (); //Empty array for input errors 

        $Input_Username = $_POST['Username'];
        $Input_Password = $_POST['Password'];
        $Input_Confirm = $_POST['ConfirmPass'];
        $Input_Email = $_POST['Email'];

        if (empty($Input_Username))
        {
            $ErrorArrays[] = "Username Is Empty";
        }
        if (empty($Input_Password))
        {
            $ErrorArrays[] = "Password Is Empty";
        }
        if ($Input_Password !== $Input_Confirm)
        {
            $ErrorArrays[] = "Passwords Do Not Match!";
        }
        if (!filter_var($Input_Email, FILTER_VALIDATE_EMAIL))
        {
            $ErrorArrays[] = "Incorrect Email Formatting";
        }

        if (count($ErrorArrays) == 0)
        {
            // No Errors
        }
        else
        {
            foreach ($ErrorArrays AS $Errors)
            {
                echo "<font color='red'><b>".$Errors."</font></b><br>";
            }
        }
    }

?>

    <form method="POST"> 
        Username: <input type='text' name='Username'> <br>
        Password: <input type='password' name='Password'><br>
        Confirm Password: <input type='password' name='ConfirmPass'><br>
        Email: <input type='text' name='Email'> <br><br>

        <input type='submit' name='Register' value='Register'>


    </form> 

This is a very basic PHP Form validation. This could be put in a try block, but for basic reference, I see this fit following our conversation in the comment box.

What this script will do, is process each of the post elements, and act accordingly, for example:

    if (!filter_var($Input_Email, FILTER_VALIDATE_EMAIL))
        {
            $ErrorArrays[] = "Incorrect Email Formatting";
        }

This will check:

if $Input_Email is not a valid email. If this is not a valid E-mail, then a message will get added to a empty array.

Further down the script, you will see:

    if (count($ErrorArrays) == 0)
    {
        // No Errors
    }
    else
    {
        foreach ($ErrorArrays AS $Errors)
        {
            echo "<font color='red'><b>".$Errors."</font></b><br>";
        }
    }

Basically. if the array count is not 0, errors have been found. Then the script will print out the errors.

Remember, this is a reference based on our conversation in the comment box, and should be used as such.

You'll have to use JS to open the popup, though you can put it on the page conditionally with PHP, you're right that you'll have to use a JavaScript function.

PHP runs on the server-side thus you have to use a client-side technology which is capable of showing popup windows: JavaScript.

So you should output a specific JS block via PHP if your form contains errors and you want to show that popup.