Bash if statement with multiple conditions throws an error

Question

I m trying to write a script that will check two error flags  and in case one flag  or both  are changed it ll echo-- error happened  My script   my error flag 0 my error flag o 0 do something      if      my error flag    1       my error flag o    2           my error flag   1   amp  amp        my error flag o   2      then     echo   my error flag  else     echo  no flag  fi   Basically  it should be  something along   if   a 1 or b 2  or  a 1 and b 2     then      display error else      no error fi   The error I get is    line 26  conditional binary operator expected  line 26  syntax error near      line 26   if      my error flag    1       my error flag o    2           my error flag   1   amp  amp    my error flag o   2      then    Are my brackets messed up

User · Answer

You can get some inspiration by reading an entrypoint.sh script written by the contributors from MySQL that checks whether the specified variables were set.

As the script shows, you can pipe them with -a, e.g.:

if [ -z "$MYSQL_ROOT_PASSWORD" -a -z "$MYSQL_ALLOW_EMPTY_PASSWORD" -a -z "$MYSQL_RANDOM_ROOT_PASSWORD" ]; then
    ...
fi

User · Answer

Please try following  if     dateR -ge 234    amp  amp     dateR -lt 238           dateR -ge 834    amp  amp     dateR -lt 838           dateR -ge 1434    amp  amp     dateR -lt 1438           dateR -ge 2034    amp  amp     dateR -lt 2038      then     echo  WORKING  else     echo  Out of range

User · Answer

You can use either    or    keyword  When you use    keyword  you have to use string operators such as -eq  -lt  I think     is most preferred for arithmetic  because you can directly use operators such as      lt  and  gt    Using    operator  a  1 b  2 if    a -eq 1    b -eq 2          a -eq 3  amp  amp  b -eq 4    then      echo  Error  else      echo  No Error  fi   Using    operator  a  1 b  2 if    a    1    b    2          a    3  amp  amp  b    4    then      echo  Error  else      echo  No Error  fi   Do not use -a or -o operators Since it is not Portable

User · Answer

Use -a  for and  and -o  for or  operations   tldp org LDP Bash-Beginners-Guide html sect 07 01 html  Update  Actually you could still use  amp  amp  and    with the -eq operation  So your script would be like this   my error flag 1 my error flag o 1 if    my error flag -eq 1          my error flag o -eq 2          my error flag -eq 1    amp  amp     my error flag o -eq 2     then       echo   my error flag  else     echo  no flag  fi   Although in your case you can discard the last two expressions and just stick with one or operation like this   my error flag 1 my error flag o 1 if    my error flag -eq 1          my error flag o -eq 2    then       echo   my error flag  else     echo  no flag  fi

[bash] Bash if statement with multiple conditions throws an error

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