If you look at the jsfiddle from question,
var str = "Abc: Lorem ipsum sit amet";
str = str.substring(str.indexOf(":") + 1);
This returns all characters after the :
, how can I adjust this to return all the characters before the :
something like
var str_sub = str.substr(str.lastIndexOf(":")+1);
but this does not work.
This question is related to
javascript
substring
In General a function to return string after substring is
function getStringAfterSubstring(parentString, substring) {_x000D_
return parentString.substring(parentString.indexOf(substring) + substring.length)_x000D_
}_x000D_
_x000D_
function getStringBeforeSubstring(parentString, substring) {_x000D_
return parentString.substring(0, parentString.indexOf(substring))_x000D_
}_x000D_
console.log(getStringAfterSubstring('abcxyz123uvw', '123'))_x000D_
console.log(getStringBeforeSubstring('abcxyz123uvw', '123'))
_x000D_
And note that first argument of subString is 0 based while second is one based.
Example:
String str= "0123456";
String sbstr= str.substring(0,5);
Output will be sbstr= 01234
and not sbstr = 012345
Another method could be to split the string by ":" and then pop off the end.
var newString = string.split(":").pop();
Source: Stackoverflow.com