printf a variable in C

Question

include  lt stdio h gt   include  lt stdlib h gt   int main         int x   1       printf  please make a selection with your keyboard n        sleep 1       printf  1  n         char input      scanf    c    amp input       switch  input            case  1               x x 1              printf x              return 0       I am trying a make a variable add to itself and then print that variable out but I can t seem to get my code to work   my output error is   newcode1 c  In function    main     newcode1 c 20 2  warning  passing argument 1 of    printf    makes pointer from integer without a cast  enabled by default  In file included from newcode1 c 1 0   usr include stdio h 362 12  note  expected    const char     restrict      but argument is of type    int    newcode1 c 20 2  warning  format not a string literal and no format arguments  -Wformat-security

User · Answer

As Shafik already wrote you need to use the right format because scanf gets you a char. Don't hesitate to look here if u aren't sure about the usage: http://www.cplusplus.com/reference/cstdio/printf/

Hint: It's faster/nicer to write x=x+1; the shorter way: x++;

Sorry for answering what's answered just wanted to give him the link - the site was really useful to me all the time dealing with C.

User · Answer

Your printf needs a format string   printf   d n   x     This reference page gives details on how to use printf and related functions

[c] printf a variable in C

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