This is my php script-
<?php
error_reporting(E_ALL);
echo('catch this -> ' ;. $thisdoesnotexist);
?>
Which obviously should show something if it were to be executed.
All I see is an empty page. Why is error_reporting(E_ALL)
not working?
<?php
ini_set("display_errors", "1");
error_reporting(E_ALL);
echo('catch this -> ' ;. $thisdoesnotexist);
?>
Does not help either. All I get is an empty page.
I've been to php.ini
and set display_errors = On
and display_startup_errors = On
.
Nothing happens.
This question is related to
php
you can try to put this in your php.ini:
ini_set("display_errors", "1");
error_reporting(E_ALL);
In php.ini file also you can set error_reporting();
In your php.ini file check for display_errors
. I think it is off.
<?php
error_reporting(E_ALL);
ini_set('display_errors', TRUE);
ini_set('display_startup_errors', TRUE);
In your php.ini file check for display_errors. If it is off, then make it on as below:
display_errors = On
It should display warnings/notices/errors .
Please read this
http://www.php.net/manual/en/errorfunc.configuration.php#ini.error-reporting
That error is a parse error. The parser is throwing it while going through the code, trying to understand it. No code is being executed yet in the parsing stage. Because of that it hasn't yet executed the error_reporting
line, therefore the error reporting settings aren't changed yet.
You cannot change error reporting settings (or really, do anything) in a file with syntax errors.
turn on display errors in your ini
http://www.php.net/manual/en/errorfunc.configuration.php#ini.display-errors
Source: Stackoverflow.com