Difference between two dates in years months days in JavaScript

Question

I ve been searching for 4 hours now  and have not found a solution to get the difference between two dates in years  months  and days in JavaScript  like  10th of April 2010 was 3 years  x month and y days ago   There are lots of solutions  but they only offer the difference in the format of either days OR months OR years  or they are not correct  meaning not taking care of actual number of days in a month or leap years  etc   Is it really that difficult to do that    I ve had a look at     http   momentjs com  -  can only output the difference in either years  months  OR days http   www javascriptkit com javatutors datedifference shtml http   www javascriptkit com jsref date shtml http   timeago yarp com  www stackoverflow com -  Search function   In php it is easy  but unfortunately I can only use client-side script on that project  Any library or framework that can do it would be fine  too   Here are a list of expected outputs for date differences     Expected output should be   1 year  5 months   diffDate new Date  2014-05-10    new Date  2015-10-10        Expected output should be   1 year  4 months  29 days   diffDate new Date  2014-05-10    new Date  2015-10-09        Expected output should be   1 year  3 months  30 days   diffDate new Date  2014-05-10    new Date  2015-09-09        Expected output should be   9 months  27 days   diffDate new Date  2014-05-10    new Date  2015-03-09        Expected output should be   1 year  9 months  28 days   diffDate new Date  2014-05-10    new Date  2016-03-09        Expected output should be   1 year  10 months  1 days   diffDate new Date  2014-05-10    new Date  2016-03-11

User · Answer

The following is an algorithm which gives correct but not totally precise since it does not take into account leap year. It also assumes 30 days in a month. A good usage for example is if someone lives in an address from 12/11/2010 to 11/10/2011, it can quickly tells that the person lives there for 10 months and 29 days. From 12/11/2010 to 11/12/2011 is 11 months and 1 day. For certain types of applications, that kind of precision is sufficient. This is for those types of applications because it aims for simplicity:

var datediff = function(start, end) {
  var diff = { years: 0, months: 0, days: 0 };
  var timeDiff = end - start;

  if (timeDiff > 0) {
    diff.years = end.getFullYear() - start.getFullYear();
    diff.months = end.getMonth() - start.getMonth();
    diff.days = end.getDate() - start.getDate();

    if (diff.months < 0) {
      diff.years--;
      diff.months += 12;
    }

    if (diff.days < 0) {
      diff.months = Math.max(0, diff.months - 1);
      diff.days += 30;
    }
  }

  return diff;
};

Unit tests

User · Answer

Time span in full Days  Hours  Minutes  Seconds  Milliseconds      Extension for Date Date difference   function  dateFrom  dateTo      var diff     TotalMs  dateTo - dateFrom      diff Days   Math floor diff TotalMs   86400000      var remHrs   diff TotalMs   86400000    var remMin   remHrs   3600000    var remS     remMin   60000     diff Hours          Math floor remHrs   3600000     diff Minutes        Math floor remMin   60000     diff Seconds        Math floor remS     1000     diff Milliseconds   Math floor remS   1000     return diff         Usage var a   new Date 2014  05  12  00  5  45  30     a  Thu Jun 12 2014 00 05 45 GMT 0400  var b   new Date 2014  02  12  00  0  25  0      b  Wed Mar 12 2014 00 00 25 GMT 0400 var diff   Date difference b  a      diff      Days  92   Hours  0   Minutes  5   Seconds  20   Milliseconds  30   TotalMs  7949120030

User · Answer

Very old thread  I know  but here s my contribution  as the thread is not solved yet   It takes leap years into consideration and does not asume any fixed number of days per month or year   It might be flawed in border cases as I haven t tested it thoroughly  but it works for all the dates provided in the original question  thus I m confident    x000D   x000D  function calculate     x000D    var fromDate   document getElementById  fromDate   value  x000D    var toDate   document getElementById  toDate   value  x000D   x000D    try   x000D      document getElementById  result   innerHTML       x000D   x000D      var result   getDateDifference new Date fromDate   new Date toDate    x000D   x000D      if  result  amp  amp   isNaN result years     x000D        document getElementById  result   innerHTML   x000D          result years     year     result years    1          s      x000D          result months     month     result months    1          s       and     x000D          result days     day     result days    1         s    x000D        x000D      catch  e    x000D      console error e   x000D      x000D    x000D   x000D  function getDateDifference startDate  endDate    x000D    if  startDate  gt  endDate    x000D      console error  Start date must be before end date    x000D      return null  x000D      x000D    var startYear   startDate getFullYear    x000D    var startMonth   startDate getMonth    x000D    var startDay   startDate getDate    x000D   x000D    var endYear   endDate getFullYear    x000D    var endMonth   endDate getMonth    x000D    var endDay   endDate getDate    x000D   x000D       We calculate February based on end year as it might be a leep year which might influence the number of days  x000D    var february    endYear   4    0  amp  amp  endYear   100    0     endYear   400    0   29   28  x000D    var daysOfMonth    31  february  31  30  31  30  31  31  30  31  30  31   x000D   x000D    var startDateNotPassedInEndYear    endMonth  lt  startMonth     endMonth    startMonth  amp  amp  endDay  lt  startDay  x000D    var years   endYear - startYear -  startDateNotPassedInEndYear   1   0   x000D   x000D    var months    12   endMonth - startMonth -  endDay  lt  startDay   1   0     12  x000D   x000D        12          12 makes sure index is always between 0 and 11 x000D    var days   startDay  lt   endDay   endDay - startDay   daysOfMonth  12   endMonth - 1    12  - startDay   endDay  x000D   x000D    return   x000D      years  years  x000D      months  months  x000D      days  days x000D       x000D    x000D   lt p gt  lt input type  text  name  fromDate  id  fromDate  placeholder  yyyy-mm-dd  value  1999-02-28    gt  lt  p gt  x000D   lt p gt  lt input type  text  name  toDate  id  toDate  placeholder  yyyy-mm-dd  value  2000-03-01    gt  lt  p gt  x000D   lt p gt  lt input type  button  name  calculate  value  Calculate  onclick  javascript calculate       gt  lt  p gt  x000D   lt p   gt  x000D   lt p id  result  gt  lt  p gt  x000D   x000D   x000D

User · Answer

Its very simple please use the code below and it will give the difference in that format according to this   3 years 9 months 3 weeks 5 days 15 hours 50 minutes   Date getFormattedDateDiff   function date1  date2    var b   moment date1     a   moment date2     intervals     years   months   weeks   days      out        for var i 0  i lt intervals length  i       var diff   a diff b  intervals i      b add diff  intervals i      out push diff         intervals i        return out join              var today     new Date     newYear   new Date today getFullYear    0  1    y2k       new Date 2000  0  1        AS OF NOV 29  2016     Time since New Year  0 years  10 months  4 weeks  0 days  console log   Time since New Year      Date getFormattedDateDiff newYear  today         Time since Y2K  16 years  10 months  4 weeks  0 days  console log   Time since Y2K      Date getFormattedDateDiff y2k  today

User · Answer

Some math is in order   You can subtract one Date object from another in Javascript  and you ll get the difference between them in milisseconds  From this result you can extract the other parts you want  days  months etc    For example   var a   new Date 2010  10  1   var b   new Date 2010  9  1    var c   a - b     c equals 2674800000                    the amount of milisseconds between September 1  2010                   and August 1  2010    Now you can get any part you want  For example  how many days have elapsed between the two dates   var days    a - b     60   60   24   1000      60   60   24   1000 is the amount of milisseconds in a day     the variable days now equals 30 958333333333332    That s almost 31 days  You can then round down for 30 days  and use whatever remained to get the amounts of hours  minutes etc

User · Answer

I do it this way  Precise  Maybe or maybe not  Try it    lt html gt     lt head gt       lt title gt  Age Calculator lt  title gt     lt  head gt      lt input type  date  id  startDate  value  2000-01-01  gt     lt input type  date  id  endDate   value  2020-01-01  gt     lt button onclick  getAge new Date document getElementById  startDate   value   new Date document getElementById  endDate   value    gt Check Age lt  button gt     lt script gt      function getAge  startDate  endDate          var diff   endDate-startDate       var age   new Date new Date  0000-01-01   getTime   diff        var years   age getFullYear         var months   age getMonth         var days   age getDate         console log years  years  months  months  days-1  days         return  years  years    months   months   days  days            lt  script gt   lt  html gt

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by using Moment library and some custom logic  we can get the exact date difference   x000D   x000D  var out  x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2015-10-10     x000D  display out   x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2015-10-09     x000D  display out   x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2015-09-09     x000D  display out   x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2015-03-09     x000D  display out   x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2016-03-09     x000D  display out   x000D   x000D  out   diffDate new Date  2014-05-10    new Date  2016-03-11     x000D  display out   x000D   x000D  function diffDate startDate  endDate    x000D    var b   moment startDate   x000D      a   moment endDate   x000D      intervals     years    months    weeks    days    x000D      out       x000D   x000D    for  var i   0  i  lt  intervals length  i      x000D      var diff   a diff b  intervals i    x000D      b add diff  intervals i    x000D      out intervals i     diff  x000D      x000D    return out  x000D    x000D   x000D  function display obj    x000D    var str       x000D    for  key in obj    x000D      str   str   obj key          key       x000D      x000D    console log str   x000D    x000D   lt script src  https   cdnjs cloudflare com ajax libs moment js 2 24 0 moment js  gt  lt  script gt  x000D   x000D   x000D

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With dayjs we did it in that way  export const getAgeDetails    oldDate  dayjs Dayjs  newDate  dayjs Dayjs    gt      const years   newDate diff oldDate   year      const months   newDate diff oldDate   month   - years   12    const days   newDate diff oldDate add years   year   add months   month     day       return       years      months      days      allDays  newDate diff oldDate   day             It calculates it perfectly including leap years and different month amount of days

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let startDate   moment new Date  2017-05-12        yyyy-MM-dd    let endDate   moment new Date  2018-09-14        yyyy-MM-dd     let Years   newDate diff date   years       let months   newDate diff date   months       let days   newDate diff date   days     console log  Year      Years     Month    months- Years 12      Days    days- Years 365 25 -  365 25  days-  Years 12    12      Above snippet will print   Year  1  Month  4  Days  2

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This code should give you desired results                              Enter your dates here                           var startDate    quot 10 05 2014 quot   var endDate    quot 11 3 2016 quot             and press  quot Run quot   you will see the result in a popup                var noofdays   0  var sdArr   startDate split  quot   quot    var startDateDay   parseInt sdArr 0    var startDateMonth   parseInt sdArr 1    var startDateYear   parseInt sdArr 2    sdArr   endDate split  quot   quot   var endDateDay   parseInt sdArr 0    var endDateMonth   parseInt sdArr 1    var endDateYear   parseInt sdArr 2     console log startDateDay     startDateMonth     startDateYear   var yeardays   365  var monthArr    31  31 30 31 30 31 31 30 31 30 31   var noofyears   0 var noofmonths   0   if  startDateYear 4   0  monthArr 1  29  else monthArr 1  28   if startDateYear    endDateYear        noofyears   0      noofmonths   getMonthDiff startDate endDate       if noofmonths  lt  0  noofmonths   0      noofdays   getDayDiff startDate endDate        else      if endDateMonth  lt  startDateMonth           noofyears    endDateYear - startDateYear -1        if noofyears  lt  1  noofyears   0     else              noofyears   endDateYear - startDateYear            noofmonths   getMonthDiff startDate endDate       if noofmonths  lt  0  noofmonths   0      noofdays   getDayDiff startDate endDate           alert noofyears   year     noofmonths   months     noofdays   days      function getDayDiff startDate endDate        if endDateDay  gt  startDateDay         noofdays   0        if endDateDay  gt  startDateDay            noofdays   endDateDay - startDateDay                 else              if  endDateYear 4   0                monthArr 1  29           else              monthArr 1    28                             if endDateMonth    1          noofdays    monthArr endDateMonth-2 -startDateDay    endDateDay          else         noofdays    monthArr 11 -startDateDay    endDateDay             return noofdays     function getMonthDiff startDate endDate           if endDateMonth  gt  startDateMonth           noofmonths   endDateMonth - startDateMonth          if endDateDay  lt  startDateDay                   noofmonths--                       else          noofmonths    12-startDateMonth    endDateMonth          if endDateDay  lt  startDateDay                   noofmonths--                        return noofmonths     https   jsfiddle net moremanishk hk8c419f

User · Answer

To calculate the difference between two dates in Years  Months  Days  Minutes  Seconds  Milliseconds using TypeScript  JavaScript  dateDifference actualDate                   Calculate time between two dates              const date1   actualDate     the date you already commented  posted             const date2  any   new Date       today              let r          object for clarity             let message  string               const diffInSeconds   Math abs date2 - date1    1000              const days   Math floor diffInSeconds   60   60   24               const hours   Math floor diffInSeconds   60   60   24               const minutes   Math floor diffInSeconds   60   60               const seconds   Math floor diffInSeconds   60               const milliseconds               Math round  diffInSeconds - Math floor diffInSeconds     1000                const months   Math floor days   31               const years   Math floor months   12                   the below object is just optional                 if you want to return an object instead of a message             r                     years  years                  months  months                  days  days                  hours  hours                  minutes  minutes                  seconds  seconds                  milliseconds  milliseconds                                check if difference is in years or months             if  years     0  amp  amp  months     0                       show in days if no years   months                 if  days  gt  0                        if  days     1                            message   days     day                         else   message   days     days                        else if  hours  gt  0                        if  hours     1                            message   hours     hour                         else                           message   hours     hours                                           else                          show in minutes if no years   months   days                     if  minutes     1                            message   minutes     minute                         else  message   minutes     minutes                                      else if  years     0  amp  amp  months  gt  0                       show in months if no years                 if  months     1                        message   months     month                     else  message   months     months                  else if  years  gt  0                       show in years if years exist                 if  years     1                        message   years     year                     else  message   years     years                               return  Posted     message     ago            this is the message a user see in the view             However  you can update the above logic for the message to show seconds and milliseconds too or else use the object  r  to format the message whatever way you want   If you want to directly copy the code  you can view my gist with the above code here

User · Answer

I ve stumbled upon this while having the same problem  Here is my code  It totally relies on the JS date function  so leap years are handled  and does not compare days based on hours  so it avoids daylight saving issues   function dateDiff start  end        let years   0  months   0  days   0         Day diffence  Trick is to use setDate 0  to get the amount of days        from the previous month if the end day less than the start day      if  end getDate    lt  start getDate              months   -1          let datePtr   new Date end           datePtr setDate 0           days   end getDate      datePtr getDate   - start getDate           else           days   end getDate   - start getDate               if  end getMonth    lt  start getMonth              end getMonth       start getMonth    amp  amp  end getDate    lt  start getDate               years   -1          months    end getMonth      12 - start getMonth           else           months    end getMonth   - start getMonth               years    end getFullYear   - start getFullYear        console log    years y   months m   days d        return  years  months  days

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How precise do you need to be  If you do need to take into account common years and leap years  and the exact difference in days between months then you ll have to write something more advanced but for a basic and rough calculation this should do the trick   today   new Date   past   new Date 2010 05 01     remember this is equivalent to 06 01 2010   dates in js are counted from 0  so 05 is june  function calcDate date1 date2        var diff   Math floor date1 getTime   - date2 getTime         var day   1000   60   60   24       var days   Math floor diff day       var months   Math floor days 31       var years   Math floor months 12        var message   date2 toDateString        message      was       message    days     days        message    months     months       message    years     years ago  n       return message         a   calcDate today past  console log a     returns Tue Jun 01 2010 was 1143 days 36 months 3 years ago   Keep in mind that this is imprecise  in order to calculate the date with full precision one would have to have a calendar and know if a year is a leap year or not  also the way I m calculating the number of months is only approximate    But you can improve it easily

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For quick and easy use I wrote this function some time ago  It returns the diff between two dates in a nice format  Feel free to use it  tested on webkit           Function to print date diffs          param  Date  fromDate  The valid start date     param  Date  toDate  The end date  Can be null  if so the function uses  now        param  Number  levels  The number of details you want to get out  1  in 2 Months  2  in 2 Months  20 Days           param  Boolean  prefix  adds  in  or  ago  to the return string     return  String  Diffrence between the two dates      function getNiceTime fromDate  toDate  levels  prefix       var lang                  date past     0  ago                date future    in  0                 date now    now                date year     0  year                date years     0  years                date years prefixed     0  years                date month     0  month                date months     0  months                date months prefixed     0  months                date day     0  day                date days     0  days                date days prefixed     0  days                date hour     0  hour                date hours     0  hours                date hours prefixed     0  hours                date minute     0  minute                date minutes     0  minutes                date minutes prefixed     0  minutes                date second     0  second                date seconds     0  seconds                date seconds prefixed     0  seconds                      langFn   function id params               var returnValue   lang id                     if params                   for var i 0 i lt params length i                         returnValue   returnValue replace     i     params i                                                return returnValue                     toDate   toDate   toDate   new Date            diff   fromDate - toDate          past   diff  lt  0   true   false          diff   diff  lt  0   diff   -1   diff          date   new Date new Date 1970 0 1 0  getTime   diff           returnString               count   0          years    date getFullYear   - 1970       if years  gt  0           var langSingle    date year     prefix                         langMultiple    date years     prefix     prefixed                 returnString     count  gt  0                  years  gt  1   langFn langMultiple  years     langFn langSingle  years             count               var months   date getMonth        if count  lt  levels  amp  amp  months  gt  0           var langSingle    date month     prefix                         langMultiple    date months     prefix     prefixed                 returnString     count  gt  0                  months  gt  1   langFn langMultiple  months     langFn langSingle  months             count           else           if count  gt  0              count   99            var days   date getDate   - 1      if count  lt  levels  amp  amp  days  gt  0           var langSingle    date day     prefix                         langMultiple    date days     prefix     prefixed                 returnString     count  gt  0                  days  gt  1   langFn langMultiple  days     langFn langSingle  days             count           else           if count  gt  0              count   99            var hours   date getHours        if count  lt  levels  amp  amp  hours  gt  0           var langSingle    date hour     prefix                         langMultiple    date hours     prefix     prefixed                 returnString     count  gt  0                  hours  gt  1   langFn langMultiple  hours     langFn langSingle  hours             count           else           if count  gt  0              count   99            var minutes   date getMinutes        if count  lt  levels  amp  amp  minutes  gt  0           var langSingle    date minute     prefix                         langMultiple    date minutes     prefix     prefixed                 returnString     count  gt  0                  minutes  gt  1   langFn langMultiple  minutes     langFn langSingle  minutes             count           else           if count  gt  0              count   99            var seconds   date getSeconds        if count  lt  levels  amp  amp  seconds  gt  0           var langSingle    date second     prefix                         langMultiple    date seconds     prefix     prefixed                 returnString     count  gt  0                  seconds  gt  1   langFn langMultiple  seconds     langFn langSingle  seconds             count           else           if count  gt  0              count   99            if prefix           if returnString                     returnString   langFn  date now              else if past              returnString   langFn  date past   returnString            else             returnString   langFn  date future   returnString              return returnString

User · Answer

Yet another solution  based on some PHP code  The strtotime function  also based on PHP  can be found here  http   phpjs org functions strtotime    Date dateDiff   function d1  d2        d1    1000      d2    1000      if  d1  gt  d2  d2    d1  d1   d2  0        var diffs             year  0          month  0          day  0          hour  0          minute  0          second  0              each diffs  function interval            while  d2  gt    d3   Date strtotime   1   interval  d1                  d1   d3                diffs interval                          return diffs       Usage    gt  d1   new Date 2000  0  1  Sat Jan 01 2000 00 00 00 GMT 0100  CET    gt  d2   new Date 2013  9  6  Sun Oct 06 2013 00 00 00 GMT 0200  CEST    gt  Date dateDiff d1  d2  Object     day  5   hour  0   minute  0   month  9   second  0   year  13

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I know it is an old thread  but I d like to put my 2 cents based on the answer by  Pawel Miech   It is true that you need to convert the difference into milliseconds  then you need to make some math  But notice that  you need to do the math in backward manner  i e  you need to calculate years  months  days  hours then minutes   I used to do some thing like this       var mins      var hours      var days      var months      var years       var diff   new Date   - new Date yourOldDate        yourOldDate may be is coming from DB  for example  but it should be in the correct format   MM dd yyyy hh mm ss fff tt        years   Math floor  diff     1000   60   60   24   365        diff   Math floor  diff     1000   60   60   24   365        months   Math floor  diff     1000   60   60   24   30        diff   Math floor  diff     1000   60   60   24   30        days   Math floor  diff     1000   60   60   24        diff   Math floor  diff     1000   60   60   24        hours   Math floor  diff     1000   60   60        diff   Math floor  diff     1000   60   60        mins   Math floor  diff     1000   60      But  of course  this is not precise because it assumes that all years have 365 days and all months have 30 days  which is not true in all cases

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I used this simple code to get difference in Years  Months  days with current date   var sdt   new Date  1972-11-30    var difdt   new Date new Date   - sdt   alert  difdt toISOString   slice 0  4  - 1970     Y      difdt getMonth   1     M     difdt getDate      D

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If you are using date-fns and if you dont want to install the  Moment js or the moment-precise-range-plugin  You can use the following date-fns function to get the same result as moment-precise-range-plugin intervalToDuration     start  new Date      end  new Date  quot 24 Jun 2020 quot       This will give output in a JSON object like below      quot years quot   0     quot months quot   0     quot days quot   0     quot hours quot   19     quot minutes quot   35     quot seconds quot   24    Live Example https   stackblitz com edit react-wvxvql Link to Documentation https   date-fns org v2 14 0 docs intervalToDuration

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Using Plane Javascript   function dateDiffInDays start  end        var MS PER DAY   1000   60   60   24      var a   new Date start       var b   new Date end        const diffTime   Math abs a - b       const diffDays   Math ceil diffTime   MS PER DAY        console log  Days     diffDays           Discard the time and time-zone information      const utc1   Date UTC a getFullYear    a getMonth    a getDate         const utc2   Date UTC b getFullYear    b getMonth    b getDate         return Math floor  utc2 - utc1    MS PER DAY      function dateDiffInDays Months Years start  end        var m1   new Date start       var m2   new Date end       var yDiff   m2 getFullYear   - m1 getFullYear        var mDiff   m2 getMonth   - m1 getMonth        var dDiff   m2 getDate   - m1 getDate         if  dDiff  lt  0            var daysInLastFullMonth   getDaysInLastFullMonth start           if  daysInLastFullMonth  lt  m1 getDate                  dDiff   daysInLastFullMonth   dDiff    m1 getDate   -   daysInLastFullMonth             else               dDiff   daysInLastFullMonth   dDiff                    mDiff--            if  mDiff  lt  0            mDiff   12   mDiff          yDiff--            console log  Y    yDiff     M    mDiff     D    dDiff     function getDaysInLastFullMonth day        var d   new Date day       console log d getDay           var lastDayOfMonth   new Date d getFullYear    d getMonth     1  0       console log  last day of month    lastDayOfMonth getDate              return lastDayOfMonth getDate        Using moment js   function dateDiffUsingMoment start  end        var a   moment start  M D YYYY        var b   moment end  M D YYYY        var diffDaysMoment   b diff a   days        console log  Moments js      diffDaysMoment        preciseDiffMoments a b     function preciseDiffMoments  a  b        var m1  a  m2 b      m1 add m2 utcOffset   - m1 utcOffset     minutes       shift timezone of m1 to m2     var yDiff   m2 year   - m1 year        var mDiff   m2 month   - m1 month        var dDiff   m2 date   - m1 date        if  dDiff  lt  0            var daysInLastFullMonth   moment m2 year      -     m2 month     1      YYYY-MM   subtract 1   M   daysInMonth            if  daysInLastFullMonth  lt  m1 date         31 01 - gt  2 03             dDiff   daysInLastFullMonth   dDiff    m1 date   -   daysInLastFullMonth             else               dDiff   daysInLastFullMonth   dDiff                    mDiff--            if  mDiff  lt  0            mDiff   12   mDiff          yDiff--            console log  getMomentum   Y    yDiff     M    mDiff     D    dDiff       Tested the above functions using following samples   var sample1   all  2 13 2018    3 15 2018         M D YYYY   30  Y  0   M  1   D  2 console log sample1    var sample2   all  10 09 2019    7 7 2020       272  Y  0   M  8   D  29 console log sample2    function all start  end        dateDiffInDays start  end       dateDiffInDays Months Years start  end        try           dateDiffUsingMoment start  end         catch  e            console log e

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I would personally use http   www datejs com   really handy  Specifically  look at the time js file  http   code google com p datejs source browse trunk src time js

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Neither of the codes work for me  so I use this instead for months and days   function monthDiff d2  d1        var months      months    d2 getFullYear   - d1 getFullYear      12      months -  d1 getMonth     1      months    d2 getMonth     1      return months  lt   0   0   months     function daysInMonth date        return new Date date getYear    date getMonth     1  0  getDate           function diffDate date1  date2        if  date2  amp  amp  date2 getTime    amp  amp   isNaN date2 getTime               var months   monthDiff date1  date2           var days   0           if  date1 getUTCDate    gt   date2 getUTCDate                  days   date1 getUTCDate   - date2 getUTCDate                      else               months--              days   date1 getUTCDate   - date2 getUTCDate     daysInMonth date2                         Use the variables months and days how you need them

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Modified this to be a lot more accurate  It will convert dates to a  YYYY-MM-DD  format  ignoring HH MM SS  and takes an optional endDate or uses the current date  and doesn t care about the order of the values   function dateDiff startingDate  endingDate        var startDate   new Date new Date startingDate  toISOString   substr 0  10        if   endingDate            endingDate   new Date   toISOString   substr 0  10         need date in YYYY-MM-DD format           var endDate   new Date endingDate       if  startDate  gt  endDate            var swap   startDate          startDate   endDate          endDate   swap            var startYear   startDate getFullYear        var february    startYear   4     0  amp  amp  startYear   100     0     startYear   400     0   29   28      var daysInMonth    31  february  31  30  31  30  31  31  30  31  30  31        var yearDiff   endDate getFullYear   - startYear      var monthDiff   endDate getMonth   - startDate getMonth        if  monthDiff  lt  0            yearDiff--          monthDiff    12            var dayDiff   endDate getDate   - startDate getDate        if  dayDiff  lt  0            if  monthDiff  gt  0                monthDiff--            else               yearDiff--              monthDiff   11                    dayDiff    daysInMonth startDate getMonth                return yearDiff    Y     monthDiff    M     dayDiff    D       Then you can use it like this      based on a current date of 2019-05-10 dateDiff  2019-05-10       0Y 0M 0D dateDiff  2019-05-09       0Y 0M 1D dateDiff  2018-05-09       1Y 0M 1D dateDiff  2018-05-18       0Y 11M 23D dateDiff  2019-01-09       0Y 4M 1D dateDiff  2019-02-10       0Y 3M 0D dateDiff  2019-02-11       0Y 2M 27D dateDiff  2016-02-11       3Y 2M 28D - leap year dateDiff  1972-11-30       46Y 5M 10D dateDiff  2016-02-11    2017-02-11       1Y 0M 0D dateDiff  2016-02-11    2016-03-10       0Y 0M 28D - leap year dateDiff  2100-02-11    2100-03-10       0Y 0M 27D - not a leap year dateDiff  2017-02-11    2016-02-11       1Y 0M 0D - swapped dates to return correct result dateDiff new Date   - 1000   60   60   24      0Y 0M 1D     Older less accurate but simpler version   RajeevPNadig s answer was what I was looking for  but his code returns incorrect values as written  This is not very accurate because it assumes  that the sequence of dates from 1 January 1970 is the same as any other sequence of the same number of days  E g  it calculates the difference from 1 July to 1 September  62 days  as 0Y 2M 3D and not 0Y 2M 0D because 1 Jan 1970 plus 62 days is 3 March      startDate must be a date string function dateAgo date        var startDate   new Date date       var diffDate   new Date new Date   - startDate       return   diffDate toISOString   slice 0  4  - 1970     Y             diffDate getMonth      M      diffDate getDate  -1     D        Then you can use it like this      based on a current date of 2018-03-09 dateAgo  1972-11-30        45Y 3M 9D  dateAgo  2017-03-09        1Y 0M 0D  dateAgo  2018-01-09        0Y 2M 0D  dateAgo  2018-02-09        0Y 0M 28D  -- a little odd  but not wrong dateAgo  2018-02-01        0Y 1M 5D  -- definitely  feels  wrong dateAgo  2018-03-09        0Y 0M 0D    If your use case is just date strings  then this works okay if you just want a quick and dirty 4 liner

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I have created  yet another one  function for this purpose   function dateDiff date        date   date split  -        var today   new Date        var year   today getFullYear        var month   today getMonth     1      var day   today getDate        var yy   parseInt date 0        var mm   parseInt date 1        var dd   parseInt date 2        var years  months  days         months     months   month - mm      if  day  lt  dd            months   months - 1               years     years   year - yy      if  month   100   day  lt  mm   100   dd            years   years - 1          months   months   12               days     days   Math floor  today getTime   -  new Date yy   years  mm   months - 1  dd   getTime       24   60   60   1000               return  years  years  months  months  days  days       Doesn t require any 3rd party libraries  Takes one argument -- date in YYYY-MM-DD format   https   gist github com lemmon d27c2d4a783b1cf72d1d1cc243458d56

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You should try using date-fns  Here s how I did it using intervalToDuration and formatDuration functions from date-fns  let startDate   Date parse  quot 2010-10-01 00 00 00 UTC quot    let endDate   Date parse  quot 2020-11-01 00 00 00 UTC quot     let duration   intervalToDuration  start  startDate  end  endDate     let durationInWords   formatDuration duration   format    quot years quot    quot months quot    quot days quot        output  10 years 1 month

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I think you are looking for the same thing that I wanted   I tried to do this using the difference in milliseconds that javascript provides  but those results do not work in the real world of dates   If you want the difference between Feb 1  2016 and January 31  2017 the result I would want is 1 year  0 months  and 0 days   Exactly one year  assuming you count the last day as a full day  like in a lease for an apartment    However  the millisecond approach would give you 1 year 0 months and 1 day  since the date range includes a leap year   So here is the code I used in javascript for my adobe form  you can name the fields    edited  there was an error that I corrected   var f1   this getField  LeaseExpiration    var g1   this getField  LeaseStart      var end   f1 value var begin   g1 value var e   new Date end   var b   new Date begin   var bMonth   b getMonth    var bYear   b getFullYear    var eYear   e getFullYear    var eMonth   e getMonth    var bDay   b getDate    var eDay   e getDate     1   if   eMonth    0    eMonth    2    eMonth    4     eMonth    6      eMonth    7     eMonth    9    eMonth    11      var eDays    31     if   eMonth    3    eMonth    5    eMonth    8     eMonth    10      var eDays   30     if  eMonth    1 amp  amp   eYear   4    0   amp  amp   eYear   100    0       eYear   400    0     var eDays   29     if  eMonth    1 amp  amp   eYear   4    0      eYear   100    0      var eDays   28      if   bMonth    0    bMonth    2    bMonth    4     bMonth    6      bMonth    7     bMonth    9    bMonth    11      var bDays    31     if   bMonth    3    bMonth    5    bMonth    8     bMonth    10      var bDays   30     if  bMonth    1 amp  amp   bYear   4    0   amp  amp   bYear   100    0       bYear   400    0     var bDays   29     if  bMonth    1 amp  amp   bYear   4    0      bYear   100    0      var bDays   28      var FirstMonthDiff   bDays - bDay   1    if  eDay - bDay  lt  0     eMonth   eMonth - 1  eDay   eDay   eDays      var daysDiff   eDay - bDay   if eMonth - bMonth  lt  0    eYear   eYear - 1  eMonth   eMonth   12     var monthDiff   eMonth - bMonth   var yearDiff   eYear - bYear   if  daysDiff    eDays    daysDiff   0  monthDiff   monthDiff   1   if  monthDiff    12    monthDiff   0  yearDiff   yearDiff   1        if   FirstMonthDiff    bDays  amp  amp  eDay - 1    eDays      daysDiff   FirstMonthDiff     event value   yearDiff     Year s           monthDiff     month s      daysDiff     days s

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Actually  there s a solution with a moment js plugin and it s very easy   You might use moment js  Don t reinvent the wheel again   Just plug Moment js Date Range Plugin     Example    x000D   x000D  var starts   moment  2014-02-03 12 53 12    x000D  var ends     moment    x000D   x000D  var duration   moment duration ends diff starts    x000D   x000D     with    moment precise date range plugin    x000D     it will tell you the difference in human terms x000D   x000D  var diff   moment preciseDiff starts  ends  true    x000D     example     years   2   months   7   days   0   hours   6   minutes   29   seconds   17   firstDateWasLater    false   x000D   x000D   x000D     or as string  x000D  var diffHuman   moment preciseDiff starts  ends   x000D     example  2 years 7 months 6 hours 29 minutes 17 seconds x000D   x000D  document getElementById  output1   innerHTML   JSON stringify diff  x000D  document getElementById  output2   innerHTML   diffHuman x000D   lt html gt  x000D   lt head gt  x000D   x000D     lt script src  https   cdnjs cloudflare com ajax libs moment js 2 14 1 moment min js  gt  lt  script gt  x000D   x000D     lt script src  https   raw githubusercontent com codebox moment-precise-range master moment-precise-range js  gt  lt  script gt  x000D   x000D   lt  head gt  x000D   lt body gt  x000D     x000D     lt h2 gt Difference between  NOW and 2014-02-03 12 53 12  lt  h2 gt  x000D     lt span id  output1  gt  lt  span gt  x000D     lt br   gt  x000D     lt span id  output2  gt  lt  span gt  x000D     x000D   lt  body gt  x000D   lt  html gt  x000D   x000D   x000D

[javascript] Difference between two dates in years, months, days in JavaScript

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