TypeError not all arguments converted during string formatting python

Question

The program is supposed to take in two names  and if they are the same length it should check if they are the same word   If it s the same word it will print  The names are the same   If they are the same length but with different letters it will print  The names are different but the same length   The part I m having a problem with is in the bottom 4 lines      usr bin env python   Enter your code for  What s In  The Length Of  A Name   here  name1   input  Enter name 1     name2   input  Enter name 2     len name1  len name2  if len name1     len name2       if name1    name2          print   The names are the same       else          print   The names are different  but are the same length       if len name1   gt  len name2           print     0   is longer than   1     name1  name2      elif len name1   lt  len name2           print     0  is longer than   1     name2  name1    When I run this code it displays   Traceback  most recent call last     File  program py   line 13  in  lt module gt      print     0   is longer than   1     name1  name2  TypeError  not all arguments converted during string formatting   Any suggestions are highly appreciated

User · Answer

There is a combination of issues as pointed out in a few of the other answers.

As pointed out by nneonneo you are mixing different String Formatting methods.
As pointed out by GuyP your indentation is off as well.

I've provided both the example of .format as well as passing tuples to the argument specifier of %s. In both cases the indentation has been fixed so greater/less than checks are outside of when length matches. Also changed subsequent if statements to elif's so they only run if the prior same level statement was False.

String Formatting with .format

name1 = input("Enter name 1: ")
name2 = input("Enter name 2: ")
len(name1)
len(name2)
if len(name1) == len(name2):
    if name1 == name2:
        print ("The names are the same")
    else:
        print ("The names are different, but are the same length")
elif len(name1) > len(name2):
    print ("{0} is longer than {1}".format(name1, name2))
elif len(name1) < len(name2):
    print ("{0} is longer than {1}".format(name2, name1))

String Formatting with %s and a tuple

name1 = input("Enter name 1: ")
name2 = input("Enter name 2: ")
len(name1)
len(name2)
if len(name1) == len(name2):
    if name1 == name2:
        print ("The names are the same")
    else:
        print ("The names are different, but are the same length")
elif len(name1) > len(name2):
    print ("%s is longer than %s" % (name1, name2))
elif len(name1) < len(name2):
    print ("%s is longer than %s" % (name2, name1))

User · Answer

In my case  it s because I need only a single  s  i missing values input

User · Answer

I encounter the error as well      mysql exceptions ProgrammingError  not all arguments converted during string formatting    But list args work well   I use mysqlclient python lib   The lib looks like not to accept tuple args  To pass list args like   arg1    arg2     will work

User · Answer

Most Easy way typecast string number to integer number 89 number int 89

User · Answer

You re mixing different format functions   The old-style   formatting uses   codes for formatting    It will cost   d dollars     95   The new-style    formatting uses    codes and the  format method   It will cost   0  dollars   format 95    Note that with old-style formatting  you have to specify multiple arguments using a tuple     d days and  d nights     40  40      In your case  since you re using    format specifiers  use  format      0   is longer than   1    format name1  name2

User · Answer

For me  This error was caused when I was attempting to pass in a tuple into the string format method   I found the solution from this question answer  Copying and pasting the correct answer from the link  NOT MY WORK     gt  gt  gt  thetuple    1  2  3   gt  gt  gt  print  this is a tuple   s     thetuple   this is a tuple   1  2  3       Making a singleton tuple with the tuple of interest as the only item    i e  the  thetuple   part  is the key bit here

User · Answer

The error is in your string formatting   The correct way to use traditional string formatting using the     operator is to use a printf-style format string  Python documentation for this here  http   docs python org 2 library string html format-string-syntax       s  is longer than   s      name1  name2    However  the     operator will probably be deprecated in the future  The new PEP 3101 way of doing things is like this      0   is longer than   1    format name1  name2

User · Answer

In addition to the other two answers  I think the indentations are also incorrect in the last two conditions  The conditions are that one name is longer than the other and they need to start with  elif  and with no indentations  If you put it within the first condition  by giving it four indentations from the margin   it ends up being contradictory because the lengths of the names cannot be equal and different at the same time        else          print   The names are different  but are the same length   elif len name1   gt  len name2       print    0  is longer than  1   format name1  name2

User · Answer

django raw sql query in view   SELECT   FROM VendorReport vehicledamage WHERE requestdate BETWEEN   0   AND   1    format date from  date to       models py   class VehicleDamage models Model       requestdate   models DateTimeField  requestdate       vendor name   models CharField  vendor name   max length 50      class Meta          managed False      views py   def location damageReports request        static date for testing     date from    2019-11-01      date to    2019-21-01      vehicle damage reports   VehicleDamage objects raw  SELECT   FROM VendorReport vehicledamage WHERE requestdate BETWEEN   0   AND   1    format date from  date to       damage report   DashboardDamageReportSerializer vehicle damage reports  many True      data   data   damage report data      return HttpResponse json dumps data   content type  application json        Note  using python 3 5 and django 1 11

User · Answer

In python 3 7 and above there is a new and easy way  here is the syntax   name    Eric  age   74 f Hello   name   You are  age      OutPut   Hello  Eric  You are 74

User · Answer

For me  as I was storing many values within a single print call  the solution was to create a separate variable to store the data as a tuple and then call the print function   x    f  id    f  name    f  age    print x

[python] TypeError: not all arguments converted during string formatting python

String Formatting with .format

String Formatting with %s and a tuple

Examples related to python

Examples related to string

Examples related to python-3.x

Examples related to typeerror

Examples related to output-formatting