Python - Create list with numbers between 2 values

Question

How would I create a list with values between two values I put in   For example  the following list is generated for values from 11 to 16   list    11  12  13  14  15  16

User · Answer

You seem to be looking for range      gt  gt  gt  x1 11  gt  gt  gt  x2 16  gt  gt  gt  range x1  x2 1   11  12  13  14  15  16   gt  gt  gt  list1   range x1  x2 1   gt  gt  gt  list1  11  12  13  14  15  16    For incrementing by 0 5 instead of 1  say    gt  gt  gt  list2    x 0 5 for x in range 2 x1  2 x2 1    gt  gt  gt  list2  11 0  11 5  12 0  12 5  13 0  13 5  14 0  14 5  15 0  15 5  16 0

User · Answer

I got here because I wanted to create a range between -10 and 10 in increments of 0 1 using list comprehension  Instead of doing an overly complicated function like most of the answers above I just did this simple range     x 0 1 for x in range -100  100     By changing the range count to 100 I now get my range of -10 through 10 by using the standard range function  So if you need it by 0 2 then just do range -200  200  and so on etc

User · Answer

While  Jared s answer for incrementing works for 0 5 step size  it fails for other step sizes due to rounding issues   np arange 11  17  0 1  tolist      11 0 11 1 11 2 11 299999999999999        16 79999999999998  16 899999999999977    Instead I needed something like this myself  working not just for 0 5     Example 11- gt 16 step 0 5 s   11 e   16 step   0 5 my list    round num  2  for num in np linspace s e  e-s  int 1 step  1  tolist       11 0  11 5  12 0  12 5  13 0  13 5  14 0  14 5  15 0  15 5  16 0     Example 0- gt 1 step 0 1 s   0 e   1 step   0 1 my list    round num  2  for num in np linspace s e  e-s  int 1 step  1  tolist       0 0  0 1  0 2  0 3  0 4  0 5  0 6  0 7  0 8  0 9  1 0

User · Answer

Use range  In Python 2 x it returns a list so all you need is    gt  gt  gt  range 11  17   11  12  13  14  15  16    In Python 3 x range is a iterator  So  you need to convert it to a list    gt  gt  gt  list range 11  17    11  12  13  14  15  16    Note  The second number is exclusive  So  here it needs to be 16 1   17  EDIT   To respond to the question about incrementing by 0 5  the easiest option would probably be to use numpy s arange   and  tolist      gt  gt  gt  import numpy as np  gt  gt  gt  np arange 11  17  0 5  tolist     11 0  11 5  12 0  12 5  13 0  13 5   14 0  14 5  15 0  15 5  16 0  16 5

User · Answer

Every answer above assumes range is of positive numbers only  Here is the solution to return list of consecutive numbers where arguments can be any  positive or negative   with the possibility to set optional step value  default   1    def any number range a b s 1       Generate consecutive values list between two numbers with optional step  default 1      if  a    b       return a else      mx   max a b      mn   min a b      result            inclusive upper limit  If not needed  delete   1  in the line below     while mn  lt  mx   1             if step is positive we go from min to max         if s  gt  0              result append mn              mn    s           if step is negative we go from max to min         if s  lt  0              result append mx              mx    s     return result   For instance  standard command list range 1 -3   returns empty list     while this function will return  -3 -2 -1 0 1   Updated  now step may be negative  Thanks  Michael for his comment

User · Answer

In python you can do this very eaisly  start 0 end 10 arr list range start end 1   output  arr  0 1 2 3 4 5 6 7 8 9 10    or you can create a recursive function that returns an array upto a given number   ar    def diff start end       if start  end          d append end          return ar     else          ar append end          return diff start-1 end     output  ar  10 9 8 7 6 5 4 3 2 1 0

User · Answer

If you are looking for range like function which works for float type  then here is a very good article   def frange start  stop  step 1 0            range    like function which accept float type         i   start     while i  lt  stop          yield i         i    step   Generate one element at a time    Preferred when you don t need all generated elements at the same time     This will save memory  for i in frange 1 0  2 0  0 5       print i     Use generated element    Generate all elements at once    Preferred when generated list ought to be small  print list frange 1 0  10 0  0 5         Output   1 0 1 5  1 0  1 5  2 0  2 5  3 0  3 5  4 0  4 5  5 0  5 5  6 0  6 5  7 0  7 5  8 0  8 5  9 0  9 5

User · Answer

assuming you want to have a range between x to y  range x y 1    gt  gt  gt  range 11 17   11  12  13  14  15  16   gt  gt  gt    use list for 3 x support

User · Answer

The most elegant way to do this is by using the range function however if you want to re-create this logic you can do something like this    def custom range  args       s   slice  args      start  stop  step   s start  s stop  s step     if 0    step          raise ValueError  range   arg 3 must not be zero       i   start     while i  lt  stop if step  gt  0 else i  gt  stop          yield i         i    step   gt  gt  gt   x for x in custom range 10  3  -1     This produces the output    10  9  8  7  6  5  4    As expressed before by  Jared  the best way is to use the range or numpy arrange however I find the code interesting to be shared

User · Answer

Try   range x1 x2 1      That is a list in Python 2 x and behaves mostly like a list in Python 3 x   If you are running Python 3 and need a list that you can modify  then use    list range x1 x2 1

User · Answer

Use list comprehension in python  Since you want 16 in the list too   Use x2 1  Range function excludes the higher limit in the function      list  x for x in range x1 x2 1

[python] Python - Create list with numbers between 2 values?

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