I found this brilliant solution here, it uses the simple logic NAN!=NAN. https://www.codespeedy.com/check-if-a-given-string-is-nan-in-python/
Using above example you can simply do the following. This should work on different type of objects as it simply utilize the fact that NAN is not equal to NAN.
import numpy as np
s = pd.Series(['apple', np.nan, 'banana'])
s.apply(lambda x: x!=x)
out[252]
0 False
1 True
2 False
dtype: bool