I am trying to get a sentence using input from the user in Java, and i need to make it lowercase and remove all punctuation. Here is my code:
String[] words = instring.split("\\s+");
for (int i = 0; i < words.length; i++) {
words[i] = words[i].toLowerCase();
}
String[] wordsout = new String[50];
Arrays.fill(wordsout,"");
int e = 0;
for (int i = 0; i < words.length; i++) {
if (words[i] != "") {
wordsout[e] = words[e];
wordsout[e] = wordsout[e].replaceAll(" ", "");
e++;
}
}
return wordsout;
I cant seem to find any way to remove all non-letter characters. I have tried using regexes and iterators with no luck. Thanks for any help.
This question is related to
java
regex
string
formatting
If you don't want to use RegEx (which seems highly unnecessary given your problem), perhaps you should try something like this:
public String modified(final String input){
final StringBuilder builder = new StringBuilder();
for(final char c : input.toCharArray())
if(Character.isLetterOrDigit(c))
builder.append(Character.isLowerCase(c) ? c : Character.toLowerCase(c));
return builder.toString();
}
It loops through the underlying char[]
in the String
and only appends the char
if it is a letter or digit (filtering out all symbols, which I am assuming is what you are trying to accomplish) and then appends the lower case version of the char
.
I don't like to use regex, so here is another simple solution.
public String removePunctuations(String s) {
String res = "";
for (Character c : s.toCharArray()) {
if(Character.isLetterOrDigit(c))
res += c;
}
return res;
}
Note: This will include both Letters and Digits
You can use following regular expression construct
Punctuation: One of !"#$%&'()*+,-./:;<=>?@[]^_`{|}~
inputString.replaceAll("\\p{Punct}", "");
You may try this:-
Scanner scan = new Scanner(System.in);
System.out.println("Type a sentence and press enter.");
String input = scan.nextLine();
String strippedInput = input.replaceAll("\\W", "");
System.out.println("Your string: " + strippedInput);
[^\w]
matches a non-word character, so the above regular expression will match and remove all non-word characters.
Source: Stackoverflow.com